Question

我想仅在JTree节点上右键单击弹出框，而不是整个JTree组件。当用户右键单击JTree节点时，弹出框出现。如果他右键单击JTree中的空格，则不应该出现。那么为什么我只能检测JTree节点的鼠标事件。我已经多次搜索网络，但找不到解决方案，所以请帮助我。

感谢。

Answer 1

这是一个简单的方法：

public static void main ( String[] args )
{
    JFrame frame = new JFrame ();

    final JTree tree = new JTree ();
    tree.addMouseListener ( new MouseAdapter ()
    {
        public void mousePressed ( MouseEvent e )
        {
            if ( SwingUtilities.isRightMouseButton ( e ) )
            {
                TreePath path = tree.getPathForLocation ( e.getX (), e.getY () );
                Rectangle pathBounds = tree.getUI ().getPathBounds ( tree, path );
                if ( pathBounds != null && pathBounds.contains ( e.getX (), e.getY () ) )
                {
                    JPopupMenu menu = new JPopupMenu ();
                    menu.add ( new JMenuItem ( "Test" ) );
                    menu.show ( tree, pathBounds.x, pathBounds.y + pathBounds.height );
                }
            }
        }
    } );
    frame.add ( tree );


    frame.pack ();
    frame.setLocationRelativeTo ( null );
    frame.setVisible ( true );
}

Answer 2

因为我最近偶然发现了这一点，我觉得它比现有的答案容易一点：

public static void main(String[] args) {
    JFrame frame = new JFrame();
    final JTree tree = new JTree();

    JPopupMenu menu = new JPopupMenu();
    menu.add(new JMenuItem("Test"));
    tree.setComponentPopupMenu(menu);
    frame.add(tree);

    frame.pack();
    frame.setLocationRelativeTo(null);
    frame.setVisible(true);
}

右键单击JTree节点摆动显示弹出框

2 个答案: