Question

我有两个类GameServer和NetworkThread。程序从其他地方创建一个套接字，然后将其传递给NetworkThread的构造函数
我只想拥有2个客户，这两个客户互相交流。 NetworkThread构造函数中的第一个客户端ID为1，另一个客户端的ID为2。但是，当我启动第二个客户端的连接时，它将永远不会进入NetworkThread类。这是我的代码：

NetworkThread类：

public class NetworkThread implements Runnable, ActionListener {

    Socket newClient;
    String userName;
    int id;

    Scanner sc = null;
    PrintWriter pw = null;

    public NetworkThread(Socket newClient, String userName, int id) {
        this.userName = userName;
        this.newClient = newClient;
        this.id = id;

        try {
            pw = new PrintWriter(newClient.getOutputStream());
            sc = new Scanner(newClient.getInputStream());
        } catch (IOException e) {
        }

        ConstructFrame();
        if (id == 1)
            changeTurnAsAGuesser();
        else
            startConnectionForSecondPlayer();
    }

    @Override
    public void run() {
    }

    private void changeTurnAsAGuesser() {   
        String word;
        String passing;

        word = JOptionPane.showInputDialog(null, "Enter Word",
                "input" + userName, JOptionPane.QUESTION_MESSAGE).toUpperCase();
        passing = "~:";
            do {
                char x = sc.nextLine().charAt(0);
                // after some works with ~> passing
                pw.println(passing);
                pw.flush();
            } while (checkWord(word, passing) == false);

                 //checkWord method returns a boolean
        } catch (Exception e) {
        }
    }
    private void startConnectionForSecondPlayer() {
        new Thread() {
            public void run() {
                while (true) {
                    String taken = sc.nextLine();
                    jf.setTitle(taken);
                }
            }
        }.start();
    }
}

GameServer类：

public class GameServer {

    static int i = 0;
    ServerSocket gameServer = null;
    String userName;

    public GameServer(String username) {
        this.userName = username;
        new Thread() {
            public void run() {
                try {
                    gameServer = new ServerSocket(4444);
                } catch (IOException e) {
                }
                while (true) {
                    try {
                        i++;
                        Socket newClient = gameServer.accept();
                        System.out.println(i);
                        Thread th = new Thread(new NetworkThread(newClient,
                                userName, i));
                        th.start();
                    } catch (UnknownHostException e) {
                    } catch (IOException e) {
                    }
                }
            }
        }.start();
    }
}

编辑：我想实现一个Hangman游戏，其中第一个客户端告诉一个单词而另一个尝试猜测该单词，但我的主要问题是我无法启动成功连接！

Answer 1

啊，我明白了。您正在NetworkThread的构造函数中执行所有工作，而不是run()方法。在构造函数中，id == 1时，在changeTurnAsAGuesser的同一个线程中调用accept。在返回之前，不会进行任何其他accept调用。

您需要做的是从构造函数中删除if (id == 1)代码并将其移动到后台线程调用的run()方法：

public NetworkThread(Socket newClient, String userName, int id) {
    ...
    ConstructFrame();
    // don't do the interactive work in the constructor
}

@Override
public void run() {
    // do it in the background thread
    if (id == 1)
        changeTurnAsAGuesser();
    else
        startConnectionForSecondPlayer();
}

在简单的服务器/套接字程序中没有完全连接

1 个答案: