无法获得选择查询工作

时间:2012-04-10 12:55:46

标签: mysql c arrays select

我想在C:中使用来自mysql数据库的Select查询

mysql_query(conn,"SELECT SI AS SUBSCRIBER_ID ,TG2 AS TAG_ID, SUM(CTR) AS NBR FROM (SELECT H.SUBSCRIBER_ID AS SI, TG.TAG_ID AS TG1,T.TAG_ID AS TG2, COUNT(TG.TAG_ID) AS COUNTER,CASE WHEN (TG.TAG_ID = T.TAG_ID) THEN COUNT(TG.TAG_ID) ELSE 0 END AS CTR from content_hits H left join  CONTENT_TAG TG ON TG.CONTENT_ID = H.CONTENT_ID LEFT JOIN TAG T ON 1= 1 GROUP BY H.SUBSCRIBER_ID, TG.TAG_ID,T.TAG_ID) AS TAB GROUP BY SI,TG2");

之后,我想使用'NBR'填充一维数组。

我试过了:

result = mysql_store_result(conn);

while ((row = mysql_fetch_row(result)))
{
  t[i]=*row['NBR'];
  printf("%d",t[i]);
}

但它不起作用。

1 个答案:

答案 0 :(得分:2)

您无法像t[i]=*row['NBR'];那样按名称访问行列。使用例如fields = mysql_fetch_fields(result);来获取列名并迭代fields数组以查找列ID“NBR”具有的列ID。然后可以在t[i]=row[id];中使用此ID。这些都在mysql连接器doc http://dev.mysql.com/doc/refman/5.0/en/mysql-fetch-fields.html