Question

我想这将是一个非常基本的问题，但我一直在寻找答案，但我无法弄清楚我的代码出错的地方。所以：我会对一个名为SerializableObject的对象进行序列化，而不是将其读回。在反序列化方法中，我得到一个临时对象，我想将其复制到另一个新的SerializeableObject，我想在之后使用，但是我无法正确复制它，但是临时对象正确地得到了值，在反序列化。这是我的课程： SeralizeableObject：

public class SerializableObject implements Serializable, Cloneable{

private Vector<int[]> mixMade;
private Vector<int[]> stepsMade;
private long time;
private int steps;
private int winnerState;

public SerializableObject(Vector<int[]> mixMade, Vector<int[]> stepsMade,
 long time, int steps, int winnerState) {
    this.mixMade = mixMade;
    this.stepsMade = stepsMade;
    this.time = time;
    this.steps = steps;
    this.winnerState = winnerState;
}

@Override
public String toString() {
    String str = "";
    for(int[] mixEl : mixMade){
        str += mixEl[0] + ", " + mixEl[1] + "|";
    }
    str += " mixes\n";
    for(int[] stepEl : stepsMade){
        str += stepEl[0] + ", " + stepEl[1] + "|";
    }
    str += " steps\n";
    str += "time: " + time + ", stepsnum: " + steps + ", 
winstate: " + winnerState;
    return str;
}    

@Override
public SerializableObject clone() {
    SerializableObject serObj;
    Vector<int[]> mixMadeTemp   = new Vector<int[]>();
    Vector<int[]> stepsMadeTemp   = new Vector<int[]>();
    for(int i = 0; i < mixMade.size(); ++i){
        mixMadeTemp.add(mixMade.get(i));
    }
    for(int i = 0; i < stepsMade.size(); ++i){
        stepsMadeTemp.add(stepsMade.get(i));
    }
    serObj = new SerializableObject(mixMadeTemp, stepsMadeTemp, 
time, steps, winnerstate);
    return serObj;
}

}

Serializator：

public class ObjectSerializator {

public ObjectSerializator() {

}

public void toFile(String filepath, SerializableObject serObj){
    ObjectOutputStream out;
    try{
        FileOutputStream fileOut = new FileOutputStream(filepath);
        out = new ObjectOutputStream(fileOut);
        out.writeObject(serObj);
    }catch (IOException ex) {

    }    
}

public void fromFile(String filepath, SerializableObject serObj){
    SerializableObject tempSerObj;
    try {
        FileInputStream fileIn = new FileInputStream(filepath);
        ObjectInputStream in = new ObjectInputStream(fileIn);

        tempSerObj = (SerializableObject) in.readObject();
        System.out.println(tempSerObj + "TEMP");
        serObj = tempSerObj.clone();

        in.close();
        fileIn.close();
    } catch (IOException ex) {

    } catch (ClassNotFoundException ex) {

    }
}

}

注意：serobj引用在fromFile方法内正确指向了良好的值一个filechooser类，用户可以从中加载文件：

public class FileChooser extends JFileChooser{

private ObjectSerializator serializator;

public FileChooser() {
    serializator = new ObjectSerializator();
}

public void load(SerializableObject serObj){
        int retValue = showOpenDialog(null);
        serializator.fromFile(getSelectedFile().getAbsolutePath(), serObj);
}}

比我的mainfram我从一个按钮

调用它

public void load(){
    SerializableObject serObj = new SerializableObject(new Vector<int[]>(), new 
Vector<int[]>(), 10, 10, 200);
    fileChooser.load(serObj);
    System.out.println(serObj + " LAST");
}

这是我的输出：

3, 2|4, 3| mixes

0, 0|0, 1|0, 0| steps

time: 6000, stepsnum: 3, winstate: 0TEMP

-------------------

 mixes

 steps

time: 10, stepsnum: 10, winstate: 200 LAST

Answer 1

您反序列化的对象会丢失。

在fromFile方法中，您有以下一行：

serObj = tempSerObj.clone();

但是serObj是该方法的一个参数。上面的行更改了 local serObj变量，而原始对象保持不变。调用方法（load）仍然保存对旧（原始）对象的引用。

您的fromFile方法不应接受SerializableObject作为参数;相反，它应该返回一个。然后FileChooser.load方法也应该返回它。最后，主框架的load方法应该类似于：

public void load() {
    SerializableObject originalObject = new SerializableObject(new Vector<int[]>(), new Vector<int[]>(), 10, 10, 200);
    // Here you can do something with the newly created object, such as save it to a file.

    SerializableObject deserializedObject = fileChooser.load();
    System.out.println(deserializedObject + " LAST");
}

无法正确地给出值序列化序列化

1 个答案: