Question

我有first.bat和second.bat。

first.bat是：call second.bat

第二个是：echo %~n0（显示正在执行的批处理的文件名）

输出为Second.bat，但我希望它显示调用者文件名，而不是它自己的文件名。

这可能吗？

Answer 1

此批处理检测调用程序脚本的名称，或者即使它直接从命令行调用

@echo off
setlocal DisableDelayedExpansion
set "func=%~0"
for /F "delims=\" %%X in ("%func:*\=%") do set "func=%%X"
if ":" == "%func:~0,1%" (
    goto %func%
)
REM *** Get the name of the caller
(
    (goto) 2>nul
    setlocal DisableDelayedExpansion
    call set "caller=%%~f0"
    call set _caller=%%caller:*%%~f0=%%
    if defined _caller (
        set "callType=batch"
        call "%~d0\:mainFunc\..%~pnx0" %*
    ) ELSE (
        set "callType=cmd-line"
        cmd /c "call "%~d0\:mainFunc\..%~pnx0" %*"
    )
    endlocal
)
echo NEVER REACHED
exit /b

:mainFunc
echo :mainFunc of %~nx0 arg1=%1 is called from '%caller%'/%callType%
exit /b

它使用(goto)语句将从堆栈中删除一个级别的事实这导致离开当前批处理文件，%~f0将是调用者脚本的名称（并且%~0该批处理的当前函数）或者在调用的情况下文本%~f0命令行。

然后使用"%~d0\:mainFunc\..%~pnx0"

再次调用自己的脚本

外部脚本

为方便使用，您可以添加帮助程序批处理文件使用此行

在您自己的脚本中使用它

@echo off
<:GetCaller <nul call GetCaller.bat myCallerVar
echo This batch was called from "%myCallerVar%"

将帮助程序批处理文件命名为 GetCaller.bat

@echo off
setlocal DisableDelayedExpansion
set "func=%~0"
for /F "delims=\" %%X in ("%func:*\=%") do set "func=%%X"
if ":" == "%func:~0,1%" (
    goto %func%
)

REM *** STEP1
REM *** Get the filename of the caller of this script, needed for later restart that
(
    (goto) 2>nul
    setlocal DisableDelayedExpansion %= it could be reenabled by the GOTO =%
    set "_returnVar=%~1"
    call set "_lastCaller=%%~f0"
    call set "_argToLastCaller=%%*"
    call "%~d0\:Step2\..%~pnx0" %*
)
exit /b %= This is never reached =%

:Step2
REM *** STEP2
REM *** Get the filename/cmd-line of the caller of the script
(
    (goto) 2>nul
    (goto) 2>nul
    setlocal DisableDelayedExpansion %= it could be reenabled by the GOTO =%    
    set "_returnVar=%_returnVar%"
    set "_lastCaller=%_lastCaller%"
    set "_argToLastCaller=%_argToLastCaller%"
    call set "caller=%%~f0"
    call set _caller=%%caller:*%%~f0=%%
    if defined _caller (
        set "callType=batch"
        call "%~d0\:Step3batch\..%~pnx0"
    ) ELSE (
        set "callType=cmd-line"
        cmd /c "call "%~d0\:Step3batch\..%~pnx0" "
    )
    endlocal
)
exit /b %= This is never reached =%

:Step3batch
REM *** STEP3 Restart the requester batch, but jump to the label :GetCaller
call :GetCaller
exit /b %= This is never reached =%

:GetCaller
REM *** This uses the trick, that starting a batch without CALL will jump to the last used label
if "%_returnVar%" NEQ "" set "%_returnVar%=%_caller%"
%_lastCaller% %_argToLastCaller%

echo #6 never reached

Answer 2

我认为最简单的方法是将第一批的文件名作为参数传递给第二批，就像这样。

REM First.bat
call Second.bat %~n0

REM Second.bat
echo %1

希望这有帮助！

Answer 3

在调用%~n0

之前，将second.bat的值存储在环境变量中

Answer 4

如果没有复杂的系统调用来检索父进程ID，或者像KurzedMetal和BaliC帖子那样将某些内容作为参数或环境变量传递，则无法执行此操作。涉及的系统调用详见this post，您必须将DLL调用导入批处理，因此这不是一件小事。

批处理（.bat）：获取第一个脚本的名称，而不是当前脚本的名称

4 个答案: