Question

我正在尝试创建一个方法，您可以输入您想要追溯的当前月份和月份的参数，并将所有这些转换为天数。例如，如果当前月份是1月份，并且我希望将过去5个月转换为数天，则答案为153.我有以下信息供您使用。

    private Calendar cal;

    private int currentMonth;

    private final int JANUARY = 31;
    private final int FEBRUARY = 28;
    private final int MARCH = 31;
    private final int APRIL = 30;
    private final int MAY = 31;
    private final int JUNE = 30;
    private final int JULY = 31;
    private final int AUGUST = 31;
    private final int SEPTEMBER = 30;
    private final int OCTOBER = 31;
    private final int NOVEMBER = 30;
    private final int DECEMBER = 31;

    public Constructor(){
        cal = new GregorianCalendar();
        currentMonth = cal.get(Calendar.MONTH);
    }


    private int convertMonthsToDays(int currentMonth, int months){
        int days;
        return days;
}

Answer 1

为什么在所有东西都是Java时制作自己的算法。

只需计算现在和之前5个月之间的毫秒数。

    long now = System.currentTimeMillis();

    Calendar calendar = GregorianCalendar.getInstance();
    //Here I set the calendar to now. But you can set the date you want.
    // by using the method  calendar.set()
    calendar.setTimeInMillis(now);
    calendar.add(Calendar.MONTH, -5);
    long previous = calendar.getTimeInMillis();

    int numberOfDays =(int)( (now - previous) / (1000* 3600 *24));

希望它有所帮助。

问候。

Answer 2

将此代码用于您想要的内容

package test;

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import org.hibernate.Criteria;
import org.hibernate.Session;
import org.hibernate.criterion.Restrictions;

import com.ibm.icu.util.Calendar;
import com.ibm.icu.util.GregorianCalendar;
import com.mPower.fw.dao.ClassMaster;
import com.mPower.fw.impl.DaoServiceIMPL;
import com.mPower.fw.util.hibernateUtil;

public class runT {

    public static void main(String[] args) throws IOException {
        try{
            Calendar calendar = new GregorianCalendar();
            int CURRENT_MONTH = 0;
            int MONTH_BACK = 5;

            int totalDays = 0;

        calendar.set(Calendar.MONTH, CURRENT_MONTH);

            for(int i=0;i<MONTH_BACK;i++){
                totalDays += calendar.getMaximum(java.util.Calendar.DAY_OF_MONTH);
                calendar.add(Calendar.MONTH, -1);
            }

            System.out.println(totalDays);

        }catch(Exception e){
            e.printStackTrace();
        }
    }

}

使用calendar.add（Calendar.MONTH， -1 ）;几个月回来。

使用calendar.add（Calendar.MONTH， 1 ）;一个月前进。

Answer 3

此实施的主要问题是它固定为2000，而不是当前年份。

private int convertMonthsToDays(int currentMonth, int months){
    int days = 0;

    for (int iter=0; iter < months; iter++)
    {
      currentMonth = (currentMonth - iter) % 12;
      this.cal.set(2000, currentMonth, 1);
      days = days + this.cal.getActualMaximum(Calendar.DAY_OF_MONTH);
    }

    return days;
}

Answer 4

我不确定你是否被允许使用SimpleDateFormat但是这里有一个非常简单的IMO示例。不知道社区对此的看法，但它有效：

private static SimpleDateFormat monthNumberFormat = new SimpleDateFormat("M");
private static SimpleDateFormat daysOfYearFormat = new SimpleDateFormat("DDD");

private static int convertMonthsToDays(int currentMonth, int months){
    try {
        Date startingDate = monthNumberFormat.parse(currentMonth + "");
        Date endingDate = monthNumberFormat.parse(currentMonth - months + "");
        return Integer.parseInt(daysOfYearFormat.format(startingDate)) - 
                Integer.parseInt(daysOfYearFormat.format(endingDate));
    } catch (ParseException e) {
        return -1;
    } catch (NumberFormatException nfe){
        return -1;
    }
}

此处没有检查您是否传递了有效参数，也没有考虑回溯一年以上。

使用此方法，您可以传递所需月份的数量和返回的月数，它将为您提供天数差异。

使用Java将一组月份转换为几天

4 个答案: