Question

我有string col= "AB21"这是一个excel小区位置。

我想将其解析为string column = "AB"＆amp; int row = 21;

我该怎么做？

Answer 1

string col = "AB21";
int startIndex = col.IndexOfAny("0123456789".ToCharArray());
string column = col.Substring(0, startIndex);
int row = Int32.Parse(col.Substring(startIndex));

当然，您应该保证输入字符串的格式正确。

Answer 2

您有一个选项是使用正则表达式来验证和解析输入字符串。请参阅下面的代码。

using System;
using System.Text.RegularExpressions;

namespace DemoRegExForStackOverflow
{
    class Program
    {
        static void Main(string[] args)
        {
            var regex = new Regex(@"(?<col>([A-Z]|[a-z])+)(?<row>(\d)+)");
            var input = @"AB12";
            var match = regex.Match(input);

            if( match != null )
            {
                var col = match.Groups["col"];
                var row = match.Groups["row"];

                Console.WriteLine("Input is: {0}", input);
                Console.WriteLine("Column is {0}", col.Value);
                Console.WriteLine("Row is {0}", row.Value);
             }
             else
             {
                 throw new ArgumentException("Invalid input");
             }
        }
    }
}

Answer 3

如果这是Excel，我会依赖Excel，因为有效范围的定义取决于版本。与之前的答案不同，此例程将拒绝看起来像范围但不是有效范围的字符串，例如Excel 2003，“XB21”或“AB66000”。我假设下面的函数可以转换为C＃。

Sub SplitRangeStg(ByVal RngStg As String, ByRef RowNum As Long, _
                                          ByRef ColNum As Long)

  Dim RngErr As Boolean

  Err.Number = 0
  RngErr = False
  On Error Resume Next
  RowNum = Range(RngStg).Row      ' Sets Err.Number if range invalid
  If Err.Number <> 0 Then
    RngErr = True
    Err.Number = 0
  End If
  ColNum = Range(RngStg).Column   ' Sets Err.Number if range invalid
  If Err.Number <> 0 Then
    RngErr = True
    Err.Number = 0
  End If
  If RngErr Then
    RowNum = 0
    ColNum = 0
    Call MsgBox(RngStg & " not recognised as an Excel range", vbOKOnly)
  End If
  On Error GoTo 0

End Sub

Answer 4

主要是为了我将来的参考：

        public static void Parse( string address )
        {
           string sheet;
           string col;
           int row;

           int sheetLength = address.IndexOf( '!' );

           if ( sheetLength > 0 )
           {
              sheet = address.Substring( 0, sheetLength );
           }
           else
           {
               sheet = string.Empty;
           }

           ++sheetLength; //skip the ! or start at 0

           int i = sheetLength;
           StringBuilder sb = new StringBuilder( );

           for( ; i < address.Length
                   && ! Char.IsDigit( address[ i ] ) 
                ; ++i )
           {
               sb.Append( address[ i ] );
           }

           col = sb.ToString( );
           sb.Clear( );

           for ( ; i < address.Length
                    && Char.IsDigit( address[ i ] )
                 ; ++i )
           {
               sb.Append( address[ i ] );
           }

           row = Int32.Parse( sb.ToString( ) );
       }

Sinde使用IndexOfAny的方法效率不高，正则表达式解决方案也不是。两种解决方案都忽略了表格。

将单元格位置字符串解析为Row＆amp;柱

4 个答案: