Question

我正在编写一个java应用程序，我需要执行以下操作。

我必须避免一周两天（外部可配置）说TUESDAY和FRIDAY做一些业务逻辑处理。我想找出下一个可用的日子。例如：如果今天是星期二，我应该在下一个可用的星期三或如果今天是星期四，那么下一个可用星期一。

有人可以指导我解决这个问题吗？这听起来很简单，但真的很棒。

这是我到目前为止所做的事情

       List<String> exceptionDays = new ArrayList<String>();
  exceptionDays.add("SUNDAY");
  exceptionDays.add("MONDAY");
  exceptionDays.add("FRIDAY");

  Date today = new Date();

      Calendar calendar = Calendar.getInstance();
      calendar.setTime(today);

  int dayOfWeek = calendar.get(Calendar.DAY_OF_WEEK);

  if (dayOfWeek == Calendar.FRIDAY) {
      calendar.add(Calendar.DATE, 3);
  } else if (dayOfWeek == Calendar.SATURDAY) {
      calendar.add(Calendar.DATE, 2);
  } else {
      calendar.add(Calendar.DATE, 1);
  }
  String strDateFormat = "E";
  SimpleDateFormat sdf = new SimpleDateFormat(strDateFormat);

  strDateFormat = "EEEE";
  sdf = new SimpleDateFormat(strDateFormat);

  Date nextBusinessDay = calendar.getTime();
  System.out.println(sdf.format(nextBusinessDay).toUpperCase());
  if(exceptionDays.contains(sdf.format(nextBusinessDay).toUpperCase())){
      if(sdf.format(nextBusinessDay).toUpperCase().equals("FRIDAY")){
          calendar.add(Calendar.DATE, 3);
      }else if(sdf.format(nextBusinessDay).toUpperCase().equals("SATURDAY")){
          calendar.add(Calendar.DATE, 2);
      } else
          calendar.add(Calendar.DATE, 1);


   nextBusinessDay = calendar.getTime();
  }
  DateFormat df = new SimpleDateFormat("dd-MMM-yy");
    String format = df.format(nextBusinessDay.getTime());
  System.out.println("Today            : " + df.format(today));
  try {
    System.out.println("Next business day: " + df.parse(format));

      System.out.println("Next business day: " + df.format(nextBusinessDay));

如果看起来很笨拙，请忽略上述逻辑。

Answer 1

简单使用Calendar

List<Integer>  avoidingDays = new ArrayList<Integer>();
avoidingDays.add(Calendar.MONDAY);
Calendar cal = Calendar.getInstance();
while(avoidingDays.contains(cal.get(Calendar.DAY_OF_WEEK)) ){cal.add(Calendar.DATE, 1}
return cal;

获取下一个有效日期

1 个答案: