这是问题"Java rounded Swing JButton"的延续。我搜索了javax.swing.JButton的扩展,它将继承所有运行时行为并且只是覆盖角的绘制。
在noah.w上使用sun forums page提供的代码,结果如下:
我希望能够在背景中使用相同的渐变,在鼠标上进行更改等等。有人知道该怎么做吗?
从图片中创建Java Swing窗口的代码是:
public class XrButton extends JButton implements MouseListener {
private static final long serialVersionUID = 9032198251140247116L;
String text;
boolean mouseIn = false;
public XrButton(String s) {
super(s);
text = s;
setBorderPainted(false);
addMouseListener(this);
setContentAreaFilled(false);
}
@Override
public void paintComponent(Graphics g) {
Graphics2D g2 = (Graphics2D) g;
if (getModel().isPressed()) {
g.setColor(g.getColor());
g2.fillRect(3, 3, getWidth() - 6, getHeight() - 6);
}
super.paintComponent(g);
if (mouseIn)
g2.setColor(Color.red);
else
g2.setColor(new Color(128, 0, 128));
g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
RenderingHints.VALUE_ANTIALIAS_ON);
g2.setStroke(new BasicStroke(1.2f));
g2.draw(new RoundRectangle2D.Double(1, 1, (getWidth() - 3),
(getHeight() - 3), 12, 8));
g2.setStroke(new BasicStroke(1.5f));
g2.drawLine(4, getHeight() - 3, getWidth() - 4, getHeight() - 3);
g2.dispose();
}
public static void main(String[] args) {
JFrame frame = new JFrame();
frame.getContentPane().setLayout(new FlowLayout());
XrButton xrButton = new XrButton("XrButton");
JButton jButton = new JButton("JButton");
frame.getContentPane().add(xrButton);
frame.getContentPane().add(jButton);
frame.setSize(150, 150);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setVisible(true);
}
public void mouseClicked(MouseEvent e) {
}
public void mouseEntered(MouseEvent e) {
mouseIn = true;
}
public void mouseExited(MouseEvent e) {
mouseIn = false;
}
public void mousePressed(MouseEvent e) {
}
public void mouseReleased(MouseEvent e) {
}
答案 0 :(得分:1)
我认为你在这里有两个选择:
1.使用组件的绘制方法实现绘图
2.为您的外观创造新的ButtonUI。在这种情况下,我建议使用Synch LAF
在这两种情况下,绘制不同的状态是你的责任
答案 1 :(得分:1)
我在Swing中看到的圆形按钮的最佳实现是物质外观:
https://substance.dev.java.net/
并非所有主题都有圆角按钮,因此您可能需要更改演示中的默认值。该项目是开源的,因此可能值得在代码中探讨一些想法。
答案 2 :(得分:1)
我也需要这样做,这就是我最终的结果(仅限Metal LAF!)
@Override
protected void paintComponent(Graphics g)
{
Graphics2D g2 = (Graphics2D) g;
g2.setRenderingHints(new RenderingHints(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON));
Shape firstClip = g.getClip();
RoundRectangle2D rect = new RoundRectangle2D.Double();
double arc = Math.ceil(getSize().getHeight()/3);
rect.setRoundRect(0, 0, Math.ceil(getSize().getWidth()), Math.ceil(getSize().getHeight()), arc, arc);
Area secondClip = new Area(getBounds());
secondClip.subtract(new Area(rect));
Area finalClip = new Area(firstClip);
finalClip.subtract(secondClip);
g2.setClip(finalClip);
super.paintComponent(g2);
Color[] gradients;
if(getModel().isRollover())
{
gradients = new Color[] { new Color(184, 207, 229), new Color(122, 138, 153), new Color(184, 207, 229) };
}
else
{
gradients = new Color[] { new Color(122, 138, 153) };
}
for(int i = 0; i < gradients.length; i++)
{
arc -= 2;
g2.setColor(gradients[i]);
g2.drawRoundRect(i+1, i+1, (int)Math.ceil(getSize().getWidth()-2)-(i*2), (int)Math.ceil(getSize().getHeight()-2)-(i*2), (int)arc, (int)arc);
}
}
答案 3 :(得分:0)
你必须自己照顾它:
GradientPaint
。顺便说一下,你必须要注意各种外观,并且你的解决方案只适合其中一种......