您好我通过实施ITemplate接口动态地将模板字段添加到gridview。 模板字段包含一些控件,如标签和文本框。我如何在行数据绑定事件中获得这些控件。
当我从aspx页面添加templatefield时,我正常做gridviewrow.findcontrol(“id”)时无法得到。
我添加模板字段的方式就像这样
public class CustomGridViewColumn : ITemplate
{
ListItemType _liType;
string _columnName;
public CustomGridViewColumn(ListItemType type, string column)
{
_liType = type;
_columnName = column;
}
void ITemplate.InstantiateIn(System.Web.UI.Control container)
{
switch (_liType)
{
case ListItemType.Header:
Label lblHeader = new Label();
lblHeader.Text = _columnName;
container.Controls.Add(lblHeader);
break;
case ListItemType.Item:
Label lblItem = new Label();
lblItem.DataBinding += new EventHandler(lbl_DataBinding);
lblItem.ID = "lbl" + _columnName;
lblItem.ClientIDMode = ClientIDMode.Predictable;
container.Controls.Add(lblItem);
DropDownList ddl = new DropDownList();
ddl.DataBinding += new EventHandler(ddl_DataBinding);
ddl.ID = "ddl" + _columnName;
ddl.Visible = false;
container.Controls.Add(ddl);
break;
}
}
}
现在我想访问我使用此代码添加的标签和下拉列表。 当我做gridviewrow.findcontrol(“id”)我没有得到它们。 任何人都可以帮助我。
当我浏览所有行并尝试查找时,我正在打算 当我选择它时,我有一个复选框,所有标签应该是diappear和ddls dhould出现 为此我正在使用以下代码。
protected void chkEdit_CheckedChanged(object sender, EventArgs e)
{
CheckBox chkEditTest = (CheckBox)sender;
GridViewRow grow = (GridViewRow)chkEditTest.NamingContainer;
DropDownList ddl = (DropDownList)grow.FindControl("ddl");
Label lbl= (Label)grow.FindControl("lbl");
}
当我这样做时,我无法获得控件。 似乎控制在回发上是令人失望的..
答案 0 :(得分:0)
这是我提出的,我可以在后面的代码中获得控件引用。
public class CustomGridViewColumn : ITemplate
{
ListItemType _liType; string _columnName;
public CustomGridViewColumn(ListItemType type, string column)
{
_liType = type;
_columnName = column;
}
void ITemplate.InstantiateIn(Control container)
{
switch (_liType)
{
case ListItemType.Header:
Label lblHeader = new Label();
lblHeader.Text = _columnName;
container.Controls.Add(lblHeader);
break;
case ListItemType.Item:
Label lblItem = new Label();
lblItem.DataBinding += new EventHandler(lblItem_DataBinding);
lblItem.ID = "lbl" + _columnName;
lblItem.ClientIDMode = ClientIDMode.Predictable;
container.Controls.Add(lblItem);
DropDownList ddl = new DropDownList();
ddl.DataBinding += new EventHandler(ddl_DataBinding);
ddl.ID = "ddl" + _columnName;
ddl.Visible = false;
ddl.DataSource = new string[] { "Hello", "World" };
container.Controls.Add(ddl);
break;
}
}
void ddl_DataBinding(object sender, EventArgs e)
{
}
void lblItem_DataBinding(object sender, EventArgs e)
{
}
}
protected void Page_Load(object sender, EventArgs e)
{
DataTable dt = new DataTable();
dt.Columns.Add("Name");
DataRow oItem = dt.NewRow();
oItem[0] = "Deepu";
dt.Rows.Add(oItem);
oItem = dt.NewRow();
oItem[0] = "MI";
dt.Rows.Add(oItem);
GridView gv = new GridView();
gv.ID = "myGridView";
gv.AutoGenerateColumns = false;
BoundField nameColumn = new BoundField();
nameColumn.DataField = "Name";
nameColumn.HeaderText = "Name";
gv.Columns.Add(nameColumn);
TemplateField TmpCol = new TemplateField();
TmpCol.HeaderText = "Template Column";
gv.Columns.Add(TmpCol);
TmpCol.ItemTemplate = new CustomGridViewColumn(ListItemType.Item, "TEST");
gv.DataSource = dt;
gv.DataBind();
Form.Controls.Add(gv);
}
protected void Button1_Click(object sender, EventArgs e)
{
GridView gv = Form.FindControl("myGridView") as GridView;
foreach (GridViewRow item in gv.Rows)
{
var ddl = item.FindControl("ddlTest") as DropDownList;
if (ddl != null)
{
ddl.Visible = true;
}
var lbl = item.FindControl("lbl") as Label;
if (lbl != null)
{
lbl.Text = "hello";
}
}
}
<form id="form1" runat="server">
<asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="Button" />
</form>
由于
迪普
答案 1 :(得分:-2)
您可以尝试使用GRIDVIEW控件的行索引
var rowIndex = int.Parse(e.CommandArgument)
GridView1.Rows[rowIndex].FindControl("id")
另请参阅
http://forums.asp.net/t/998368.aspx/1
http://www.codeproject.com/Articles/12021/Accessing-the-different-controls-inside-a-GridView
http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.gridviewrow.aspx
由于
迪普