Question

我有一个包含一系列（IP varchar（15），DateTime datetime2）值的表。每行对应于用户发出的HTTP请求。我想为这些行分配会话号。不同的IP地址具有不同的会话号。如果最后一个请求超过30分钟，则应为同一IP分配新会话号。这是一个示例输出：

IP, DateTime, SessionNumber, RequestNumber 1.1.1.1, 2012-01-01 00:01, 1, 1 1.1.1.1, 2012-01-01 00:02, 1, 2 1.1.1.1, 2012-01-01 00:03, 1, 3 1.1.1.2, 2012-01-01 00:04, 2, 1 --different IP => new session number 1.1.1.2, 2012-01-01 00:05, 2, 2 1.1.1.2, 2012-01-01 00:40, 3, 1 --same IP, but last request 35min ago (> 30min)

第1列和第2列是输入，3和4是所需的输出。该表显示了两个用户。

由于底层是表格真的很大，如何有效地解决这个问题？我更喜欢在数据上传递少量的传递（一两次）。

Answer 1

这里有几次尝试。

;WITH CTE1 AS
(
SELECT *,
IIF(DATEDIFF(MINUTE,
       LAG(DateTime) OVER (PARTITION BY IP ORDER BY DateTime),
       DateTime) < 30,0,1) AS SessionFlag
FROM Sessions
), CTE2 AS
(
SELECT *,
       SUM(SessionFlag) OVER (PARTITION BY IP 
                                  ORDER BY DateTime) AS IPSessionNumber
FROM CTE1
)
SELECT IP,
       DateTime,
       DENSE_RANK() OVER (ORDER BY IP, IPSessionNumber) AS SessionNumber,
       ROW_NUMBER() OVER (PARTITION BY IP, IPSessionNumber 
                              ORDER BY DateTime) AS RequestNumber
FROM CTE2

这有两个排序操作（按IP, DateTime然后按IP, IPSessionNumber），但假设可以任意分配SessionNumber，只要为每个新的分配不同的唯一会话编号每个ip地址/ 30分钟规则的会话。

按时间顺序依次分配SessionNumber s。我使用了以下内容。

;WITH CTE1 AS
(
SELECT *,
IIF(DATEDIFF(MINUTE,
       LAG(DateTime) OVER (PARTITION BY IP ORDER BY DateTime),
       DateTime) < 30,0,1) AS SessionFlag
FROM Sessions
), CTE2 AS(
SELECT *,
       SUM(SessionFlag) OVER (ORDER BY DateTime) AS GlobalSessionNo
FROM CTE1
), CTE3 AS(
SELECT *,
       MAX(CASE WHEN SessionFlag = 1 THEN GlobalSessionNo END) 
               OVER (PARTITION BY IP ORDER BY DateTime) AS SessionNumber
FROM CTE2)
SELECT IP,
       DateTime,
       SessionNumber,
       ROW_NUMBER() OVER (PARTITION BY SessionNumber 
                              ORDER BY DateTime) AS RequestNumber
FROM CTE3

然而，这会将排序操作的数量增加到4个。

Answer 2

这是一个使用表变量和row_number来创建可以在递归CTE中使用的ID的版本。将性能与游标和一个查询（由Martin提供）版本进行比较可能是值得的。

CREATE TABLE #T
(
  IP varchar(15),
  DateTime datetime,
  ID int,
  primary key (IP, ID)
)

insert into #T(IP, DateTime, ID)
select IP, DateTime, row_number() over(partition by IP order by DateTime) 
from #sessionRequests

;with C as
(
  select IP,
         ID,
         DateTime,
         1 as Session
  from #T
  where ID = 1
  union all 
  select T.IP,
         T.ID,
         T.DateTime,
         C.Session + case when datediff(minute, C.DateTime, T.DateTime) >= 30 then 1 else 0 end
  from #T as T
    inner join C 
      on T.IP = C.IP and
         T.ID = C.ID + 1
)
SELECT IP,
       DateTime,
       dense_rank() over(order by IP, Session) as SessionNumber,
       row_number() over(partition by IP, Session order by DateTime) as RequestNumber
from C
order by IP, DateTime, SessionNumber, RequestNumber
option (maxrecursion 0)

SQL Server：row_number按超时分区

2 个答案: