Question

作为一个例子，如果我有这个数组：

_mode = [NSArray arrayWithObjects:
                      [NSArray arrayWithObjects:@"1", @"One", nil],
                      [NSArray arrayWithObjects:@"2", @"Two", nil],
                      [NSArray arrayWithObjects:@"3", @"Three", nil],
                      [NSArray arrayWithObjects:@"4", @"Four", nil],
                      [NSArray arrayWithObjects:@"5", @"Five", nil],
                      nil];

我需要找到数组_mode的哪个对象包含@"3"我该怎么做？我尝试了selectedIndex = [_mode indexOfObject:@"3"];和selectedIndex = [[_mode objectAtIndex:0] indexOfObject:@"sta"];，但都没有工作。

Answer 1

[_mode indexOfObjectPassingTest:^(id obj, NSUInteger idx, BOOL *stop){
    return [[obj objectAtIndex:0] isEqualToString:@"3"];
}];

Answer 2

这与Jonas Schnelli的回答基本相同：）

for (NSArray *subarray in _mode){
    NSInteger index = [subarray indexOfObject:@"3"];
    if (index != NSNotFound) return subarray;
}

Answer 3

像这样？

for(NSArray *subarray in _mode) {
  for(NSString *str in subarray) {
   if([str isEqualToString:@"3"]) {
     return subarray; // returns the array within _mode that contains "3"
   }
  }
}

如果您需要索引：

for(NSArray *subarray in _mode) {
  for(NSString *str in subarray) {
   if([str isEqualToString:@"3"]) {
     return [mode indexOfObject:subarray];
   }
  }
}

Answer 4

这给出了数组中字典的索引。

for (NSDictionary *dict in self.yourArray ) {
    if ([anotherArray containsObject:[dict valueForKey:@"Key"]]) {
        NSIndexPath *indexPath = [NSIndexPath indexPathForRow:[self.yourArray indexOfObject:dict] inSection:section];
        NSLog(@"IndexPath is %@",indexPath);
    }    
}

在数组对象中查找数组对象的索引

4 个答案: