Question

我使用了一个生成器来创建s

s= generator(n)

生成器yeilds（a，b）用于范围（n）中的n。其中a = [w，x]和b = [y，z]

使用

打印

for i in s:
    print i

返回：

([0.27704232355167768, 0.44459304959240675], [0.4387731877846518, 0.38108111684466683])
([0.27704232355167768, 0.44459304959240675], [0.6362447250743466, 0.72047209074359853])
([0.27704232355167768, 0.44459304959240675], [0.65419386891877318, 0.025362727486327286])
([0.27704232355167768, 0.44459304959240675], [0.039966264334369672, 0.9662795347591735])

但是我想要

0.27704232355167768 0.44459304959240675 0.4387731877846518 0.38108111684466683
0.27704232355167768 0.44459304959240675 0.6362447250743466 0.72047209074359853
0.27704232355167768 0.44459304959240675 0.65419386891877318 0.025362727486327286
0.27704232355167768 0.44459304959240675 0.039966264334369672 0.9662795347591735

我尝试了以下想法的许多变体

print '\n'.join('\t'.join(x) for x in s)

但是对于n0有用并倾向于以相同的格式返回s。任何人都可以帮我解决这个问题吗？

Answer 1

>>> from itertools import chain
>>> for i in s:
        print '\t'.join(map(str,chain(*i)))


0.277042323552 0.444593049592 0.438773187785 0.381081116845
0.277042323552 0.444593049592 0.636244725074 0.720472090744
0.277042323552 0.444593049592 0.654193868919 0.0253627274863
0.277042323552 0.444593049592 0.0399662643344 0.966279534759

Answer 2

from itertools import chain
'\n'.join('\t'.join(map(str,tuple(chain(*i)))) for i in s)

chain展平每一行，因此您只需使用制表符连接所有元素，然后使用换行符连接行。

Answer 3

不确定您的发电机是什么样的，但看看您的示例，如果您的发电机如下

>>> def generator(n):
    for i in xrange(0,n):
        yield ([0.27704232355167768, 0.44459304959240675], [0.4387731877846518, 0.38108111684466683])
    return

那么你可以像

那样

>>> s=generator(5)
>>> print '\n'.join('\t'.join(map(str,x))  for x in s)
[0.2770423235516777, 0.44459304959240675]   [0.4387731877846518, 0.38108111684466683]
[0.2770423235516777, 0.44459304959240675]   [0.4387731877846518, 0.38108111684466683]
[0.2770423235516777, 0.44459304959240675]   [0.4387731877846518, 0.38108111684466683]
[0.2770423235516777, 0.44459304959240675]   [0.4387731877846518, 0.38108111684466683]
[0.2770423235516777, 0.44459304959240675]   [0.4387731877846518, 0.38108111684466683]
>>>

生成器对象进入制表符分隔文本

3 个答案: