我的表格中有两个字段。
1)Html选择字段项(来自mysql数据库)
2)名称框。
如果用户从html选择标签中选择一个项目并忘记写下他/她的名字,那么用php就可以了..
* Your username required
但是它没有显示用户选择的选择项目..它再次显示选择... 这就是为什么会出现另一条错误消息..
* Please select your item.
如何使用php显示此选定项目?
Html格式:
<tr>
<td>Class</td>
<td>
<select class="td" name="class">
<option selected="selected" value="">Select..</option>
<?php
include_once("../../toplevel/content/manage/dbcon/dbcon.php");
$sql = mysql_query("SELECT * FROM class");
while($re = mysql_fetch_array($sql))
{
$re_class = mysql_real_escape_string(trim($re['c_name']));
echo "<option value='$re_class'> $re_class </option>";
}
?>
</select>
</td>
</tr>
<tr>
<td>Name</td>
<td><input type="text" value="<?php if(isset($_POST['uname'])) echo
$_POST['uname']; ?>" name="uname" class="td" /></td>
</tr>
<tr>
我可以为Name提交这个但是我如何为select字段执行此操作?
非常感谢。
Shibbir
答案 0 :(得分:0)
<tr>
<td>Class</td>
<td>
<select class="td" name="class" onchange="this.form.submit();">
<option selected="selected" value="">Select..</option>
<?php
include_once("../../toplevel/content/manage/dbcon/dbcon.php");
$sql = mysql_query("SELECT * FROM class");
while($re = mysql_fetch_array($sql))
{
$re_class[] = mysql_real_escape_string(trim($re['c_name']));
}
?>
<?php for($i = 0; $i < count($re_class); $i++) { ?>
<?php echo "<option value='$re_class[$i]'";
if($re_class[$i] == $_POST['class']) { echo "selected=selected"; } ?> <?php echo ">" . $re_class[$i] . </option>"; ?>
<?php } ?>
</select>
</td>
</tr>
<tr>
<td>Name</td>
<td><input type="text" value="<?php if(isset($_POST['uname'])) echo
$_POST['uname']; ?>" name="uname" class="td" /></td>
</tr>
<tr>
修改如果当前$_POST
变量等于$re_class
数组中的选项,您似乎希望选择选项值。
答案 1 :(得分:0)
<tr>
<td>Class</td>
<td>
<select class="td" name="class">
<option value="">Select..</option>
<?php
include_once("../../toplevel/content/manage/dbcon/dbcon.php");
$sql = mysql_query("SELECT * FROM class");
while($re = mysql_fetch_array($sql))
{
$re_class = mysql_real_escape_string(trim($re['c_name']));
if(isset($_POST['class'])){
echo '<option '.($_POST['class']==$re_class?'selected':'').' value='.$re_class.'>'.$re_class.'</option>';
}else{
echo '<option value='.$re_class.'>'.$re_class.'</option>';
}
}
?>
</select>
</td>
</tr>
<tr>
<td>Name</td>
<td><input type="text" value="<?php if(isset($_POST['uname'])) echo
$_POST['uname']; ?>" name="uname" class="td" /></td>
</tr>
<tr>
答案 2 :(得分:0)
<tr>
<td>Class</td>
<td>
<select class="td" name="class">
<option value="">Select..</option>
<?php
include_once("../../toplevel/content/manage/dbcon/dbcon.php");
$sql = mysql_query("SELECT * FROM class");
while($re = mysql_fetch_array($sql))
{
$re_class = mysql_real_escape_string(trim($re['c_name']));
$sel='';
if($re_class==$_POST['class']) {
$sel='selected="selected"';
}
echo "<option value='$re_class' ".$sel."> $re_class </option>";
}
?>
</select>
</td>
</tr>
<tr>
<td>Name</td>
<td><input type="text" value="<?php if(isset($_POST['uname'])) echo
$_POST['uname']; ?>" name="uname" class="td" /></td>
</tr>
<tr>
你是说这个吗?