Question

我有以下查询，没有,SUM(amount) AS total它可以正常工作。现在问题是我想从我的表vouchers中选择所有值，同时想要从另一个名为amount的表中获取字段details的总和值。 / p>

SELECT *,SUM(amount) AS total FROM vouchers 
LEFT JOIN details on vouchers.voucher_no = details.voucher_no 
 LEFT JOIN   accounts on accounts.code = vouchers.account_code 
 WHERE (voucher_type='1' AND t_code=$code)

我尝试了上面的查询，但它向我显示了以下错误。（请查看链接）

http://i44.tinypic.com/bdaq.png

Answer 1

将details和放入子查询中，LEFT JOIN对应子查询。您的原始广告缺少GROUP BY汇总的SUM()条款。

SELECT
  vouchers.*,
  /* from the subquery... */
  detailssum.total
FROM
  vouchers
  LEFT JOIN (
    /* Subquery gets total per voucher_no to join against vouchers */
    SELECT voucher_no, t_code, SUM(amount) as total FROM details GROUP BY voucher_no
  ) detailssum ON vouchers.voucher_no = detailssum.voucher_no
  LEFT JOIN accounts on accounts.code = vouchers.account_code 
WHERE (voucher_type='1' AND t_code=$code)

（我们假设$code已经包含已清理和边界检查的值）

选择所有值并同时汇总来自不同表的字段值

1 个答案: