我必须创建一个程序,从两个已经按字母顺序排列的文件中读取名称和ID号,并将它们完全按字母顺序组合在第三个文件上。文件的组织方式如下......
姓氏,名字 ID(例如rbb091020) 姓氏,名字 ID
由于某种原因,我的文件读取了两个文件并创建了第三个文件,但它没有向第三个文件写入任何内容。
这是我的代码......
import java.io.*;
import java.util.Scanner;
public class Combine_Files
{
public static void main(String[]args) throws IOException
{
String filename1 = "";
String filename2 = "";
String combinedFileName = "";
String response = "";
String nextName1 = "";
String nextName2 = "";
String nextIDNumber1 = "";
String nextIDNumber2 = "";
boolean okToOverwrite = false;
Scanner keyboard = new Scanner(System.in);
System.out.println("What is the name of the first file?");
filename1 = keyboard.nextLine();
File file1 = new File(filename1);
if (!file1.exists())
{
System.out.println(file1 + " does not exist.\nTerminating Program.");
System.exit(0);
}
System.out.println("What is the name of the second file?");
filename2 = keyboard.nextLine();
File file2 = new File (filename2);
if (!file2.exists())
{
System.out.println(file2 + " does not exist.\nTerminating Program.");
System.exit(0);
}
System.out.println("What is the name of the file that you wish to create?");
combinedFileName = keyboard.nextLine();
File combinedFile = new File (combinedFileName);
while (combinedFile.exists() && !okToOverwrite)
{
System.out.println("\nError, a file named " +
combinedFileName + " already exists." +
"\nWould you like to overwrite this file?" +
"\nEnter Y for Yes or N for No.");
response = keyboard.nextLine();
// Add input validation on response
if (response.equalsIgnoreCase("Y"))
{
okToOverwrite = true;
}
else
{
System.out.println("Enter a new filename.");
combinedFileName = keyboard.nextLine();
combinedFile = new File(combinedFileName);
}
}
if (file1.exists() && file2.exists())
{
Scanner list1 = new Scanner(file1);
Scanner list2 = new Scanner(file2);
PrintWriter outputFile = new PrintWriter(combinedFile);
while (list1.hasNext() && list2.hasNext())
{
nextName1 = list1.nextLine();
nextName2 = list2.nextLine();
if(nextName1.compareToIgnoreCase(nextName2) <0)
{
outputFile.print(nextName1);
nextName1 = list1.nextLine();
outputFile.print(nextName1);
}
else if(nextName1.compareToIgnoreCase(nextName2) >0)
{
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
else
{
outputFile.println(nextName1);
nextName1 = list1.nextLine();
outputFile.println(nextName1);
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
}
while (list1.hasNext() && !list2.hasNext())
{
outputFile.println(nextName1);
}
while (list2.hasNext() && !list1.hasNext())
{
outputFile.println(nextName2);
}
}
}
}
答案 0 :(得分:1)
当您使用像PrintWriter
这样的编写器类时,您需要确保每次要将某些内容打印到STDOUT或文件时调用flush()
方法。所以基本上每当你调用它写入内部缓冲区的任何PrintWriter
打印方法时,对flush()
的调用就会将缓冲区发送到适当的输出流。
while (list1.hasNext() && list2.hasNext())
{
nextName1 = list1.nextLine();
nextName2 = list2.nextLine();
if(nextName1.compareToIgnoreCase(nextName2) <0)
{
outputFile.print(nextName1);
nextName1 = list1.nextLine();
outputFile.print(nextName1);
}
else if(nextName1.compareToIgnoreCase(nextName2) >0)
{
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
else
{
outputFile.println(nextName1);
nextName1 = list1.nextLine();
outputFile.println(nextName1);
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
outputFile.flush(); // <--- flush added here
}
while (list1.hasNext() && !list2.hasNext())
{
outputFile.println(nextName1);
outputFile.flush(); // <--- flush added here
}
while (list2.hasNext() && !list1.hasNext())
{
outputFile.println(nextName2);
outputFile.flush(); // <--- flush added here
}
对flush()
的这些调用应该写入文件。
答案 1 :(得分:0)
此程序存在逻辑错误。当我测试长度不均匀的文件时,它会在最后两个while循环之一中陷入无限循环,并且确实会写入输出文件,直到程序被强制终止。如果文件长度相同,则扫描程序无法读取其中一个if / else子句中的行。