我有两个单独的SELECT语句,它们分别是GROUP-BY,例如:
SELECT x, y, z FROM a GROUP BY x
SELECT x, n, o FROM b GROUP BY x
我非常希望将这两个SELECT连接在一起以组合它们的列,例如:
SELECT x as x1, y, z FROM a GROUP BY x
LEFT JOIN (
SELECT x as x2, n, o FROM b GROUP BY x)
ON x1=x2;
这可能吗?我问,因为MySQL在抱怨
您的SQL语法有错误; 检查对应的手册 您的MySQL服务器版本 正确的语法在'LEFT JOIN附近使用 选择 x为x2
如果可以的话,对我的语法有什么问题的想法?
非常感谢!
答案 0 :(得分:5)
这有效
select * from (
(select 1 a,2 b,3 c) t1 left join (select null a,2 b,5 c) t2 on (t1.b=t2.b)
);
可替换地,
select * from (
(select 1 a,2 b,3 c) t1 left join (select null a,2 b,5 c) t2 using (b)
);
两者都会导致
+---+---+---+------+---+---+
| a | b | c | a | b | c |
+---+---+---+------+---+---+
| 1 | 2 | 3 | NULL | 2 | 5 |
+---+---+---+------+---+---+
1 row in set (0.00 sec)
答案 1 :(得分:4)
有几种方法可以实现这一目标:
SELECT a.x, y, z, n, o FROM a INNER JOIN b ON a.x = b.x GROUP BY a.x, b.x;
SELECT * FROM (SELECT x, y, z FROM a GROUP BY x) AS a INNER JOIN (SELECT x, n, o FROM b GROUP BY x) AS b ON a.x = b.x;
答案 2 :(得分:1)
您也可以使用此查询:
SELECT a.x, a.y, a.z, b.x, b.o, b.n
FROM a, (SELECT x, n, o FROM b GROUP BY x) as b
WHERE a.x = b.x
GROUP BY a.x;