Question

这是我的代码 -

<?php
    $con = mysql_connect('db', 'table', 'p/w');
    if (!$con) {
        die('Could not connect: ' . mysql_error()); }
    mysql_select_db("db", $con);
    $result = mysql_query("SELECT * FROM computers WHERE KEYWORDS='Computers,Desktops'");
    echo "<table border='1' width='100%'  >";
    while($row = mysql_fetch_array($result)) {
        echo "<tr>";
        echo "<td>" . $row['NAME'] . "</td>";
        echo "<td>" . $row['MANUFACTURER'] . "</td>";

我想在其中一列

中显示来自db存储为路径的图像

echo "</tr>"; }
echo "</table>";
mysql_close($con);
?>

任何人都可以帮忙吗？感谢

Answer 1

<?php 
$con = mysql_connect('db', 'table', 'p/w'); 
if (!$con) { die('Could not connect: ' . mysql_error()); } 
mysql_select_db("db", $con); 
$result = mysql_query("SELECT * FROM computers WHERE KEYWORDS='Computers,Desktops'"); 
echo "<table border='1' width='100%' >"; 
    while($row = mysql_fetch_array($result)) { 
        echo "<tr>";
        echo "<td>" . $row['NAME'] . "</td>"; 
        echo "<td>" . $row['MANUFACTURER'] . "</td>";
        echo "<td><img src='folder_name/".$row['image_name']."'></td>";
        echo "</tr>"; 
    }
echo "</table>";
mysql_close($con);
?>

folder_name =保存图像的文件夹的名称
image_name =表名计算机中图片的字段名称

Answer 2

您可以在任何地方使用img元素来显示图像。

echo "<img src='" . $row['image'] . "'>"。您还可以查看img element for HTML或img element for HTML5

如何使用php将图像从mysql显示到表格

2 个答案: