我正在学习mysql,我遇到了一个产生#1066的表的问题 - 错误不是唯一的表别名。我尝试了许多不同的查询,但都有相同的结果。有人可以让我摆脱痛苦,帮助指出我做错了什么! - 谢谢
表
looks
---------
look_id(Pk)
user_id
title
description
date_modified
Add_Look_Item
-----------------------
look_id (fk from table 1)
item_id (fk from table 3)
Item
--------------
item_id (pk)
name
details
Add_Images
-------------------
image_id (pk)
item_id (fk from table 3)
image_name
我试过的查询 - add_look_item是复合键
SELECT DISTINCT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name FROM looks JOIN add_look_item ON add_look_item.look_id = looks.look_id
JOIN add_look_item ON add_look_item.item_id = item.item_id WHERE look.user_id = 94
#1066 - error not unique table alias 'add_look_item
SELECT DISTINCT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name FROM looks JOIN
add_look_item ON add_look_item.looks_id = look.look_id
JOIN add_look_item ON add_look_item.item_id = item.item_id
JOIN add_images ON add_images.item_id = item.item_id WHERE add_look_item.item_id = item.item_id AND look.user_id = 94
#1066 - error not unique table alias 'add_look_item
SELECT DISTINCT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name FROM looks INNER JOIN add_look_item ON add_look_item.look_id = look_look_id
INNER JOIN add_images ON add_images.item_id = item.item_id
INNER JOIN add_look_item ON add_look_item.item_id = item.item_id
WHERE look.user_id = 94
#1066 - error not unique table alias 'add_look_item
SELECT DISTINCT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name FROM looks
INNER JOIN add_look_item ON add_look_item.looks_id = look.look_id
INNER JOIN add_images ON add_images.item_id = item.item_id
INNER JOIN add_look_item ON add_look_item.item_id = item.item_id
WHERE add_look_item.item_id = item.item_id AND look.user_id = 94
#1066 - error not unique table alias 'add_look_item
SELECT DISTINCT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name FROM looks
INNER JOIN add_look_item ON add_look_item.looks_id = look.look_id
INNER JOIN add_images ON add_images.item_id = item.item_id
WHERE add_look_item.item_id = item.item_id AND look.user_id = 94
#1054 - Unknown column 'item.item_id' in 'where clause'
由于
答案 0 :(得分:1)
为add_look_item创建一个别名,因为您多次加入它。
例如:
SELECT tbl.a, a.y, b.y
FROM tbl
JOIN tbl2 as a ON tbl.x = a.x
JOIN tbl2 as b ON tbl.x = b.x
否则查询引擎将不知道该怎么做:)
答案 1 :(得分:1)
试试这个 -
SELECT looks.look_id, looks.title, looks.date_modified, add_look_item.item_id, add_images.image_name
FROM looks
JOIN add_look_item
ON looks.look_id = add_look_item.look_id
JOIN add_images
ON add_look_item.item_id = add_images.item_id
WHERE look.user_id = 94