我希望能够通过升序或降序对[评论]进行排序。我已尝试在“order by”子句中再次执行聚合,但这不起作用。我也尝试在子查询之外进行排序,这让我使用了别名[comment],但是只在第0行和第10行之间进行了排序。
此查询是更大查询的较小版本。
SELECT *
FROM (SELECT ISNULL((SELECT COUNT("order")
FROM order_comment
WHERE "order" = "order"."id"
GROUP BY "order"), 0) AS [comment],
Row_number() OVER (ORDER BY "order"."id" DESC) AS [rownum]
FROM [order]
WHERE ISNULL((SELECT COUNT("order")
FROM order_comment
WHERE "order" = "order"."id"
GROUP BY "order"), 0) > 0) AS [filter]
WHERE [rownum] BETWEEN 0 AND 10
在MySql中如此简单!
SELECT Ifnull((SELECT COUNT(`order`)
FROM order_comment
WHERE `order` = `order`.`id`
GROUP BY `order`), 0) AS `comment`
FROM `order`
HAVING `comment` > 0
ORDER BY `comment` DESC
LIMIT 0, 10
答案 0 :(得分:5)
按照最新的编辑嫌疑人你想要这样的东西
;WITH oc AS
(
SELECT [order],
COUNT([order]) AS order_count
FROM order_comment
GROUP BY [order]
), occ AS
(
SELECT o.*,
order_count AS comment,
ROW_NUMBER() OVER (ORDER BY order_count DESC) AS [rownum]
FROM [order] o
INNER JOIN oc ON oc.[order] = o.id
)
SELECT *
FROM occ
WHERE [rownum] BETWEEN 0 AND 10
ORDER BY [rownum]
INNER JOIN
已排除order_comment
答案 1 :(得分:0)
我认为您不知道可以将OVER
clause与聚合函数一起使用。
COUNT(order) OVER(PARTITION BY id) AS [comment]
....
ORDER BY [comment]
答案 2 :(得分:0)
在SQL Server中,您可以按查询中的列号排序,如ORDER BY 1中所示 更多信息http://blog.sqlauthority.com/2010/12/27/sql-server-order-by-columnname-vs-order-by-columnnumber/
SELECT *
FROM (SELECT ISNULL((SELECT COUNT("order")
FROM order_comment
WHERE "order" = "order"."id"
GROUP BY "order"), 0) AS [comment],
Row_number() OVER (ORDER BY "order"."id" DESC) AS [rownum]
FROM [order]
WHERE ISNULL((SELECT COUNT("order")
FROM order_comment
WHERE "order" = "order"."id"
GROUP BY "order"), 0) > 0) AS [filter]
WHERE [rownum] BETWEEN 0 AND 10
ORDER BY 1