Question

我想要做的是我的应用程序向其发送消息的数字被传递给BraodcastReceiver ...但到目前为止我要么为null，要么BroadcastReceiver只是崩溃..

这是我对CreateMessage类中的BroadcastReceiver的意图......

        Intent intent = new Intent();
        Bundle bundle = new Bundle();
        bundle.putString("phN", phoneNo);
        intent.putExtras(bundle);
        startActivity(intent);

在BroadcastReceiver（SmsReceiver类）中，我试图抓住这样的意图..

public void onReceive(Context context, Intent intent) {
    //---get the SMS message passed in---
    Bundle bundle = intent.getExtras();
    try{
    //receiveNumbers = intent.getExtras().get("phN").toString();
        String  receiveNumbers = intent.getStringExtra("phN");
        Toast.makeText(context, receiveNumbers, Toast.LENGTH_LONG).show();
    }catch(Exception e){
        e.printStackTrace();
    }

我的清单文件：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
      package="com.AEM_n"
      android:versionCode="2" android:versionName="2.0">
    <uses-sdk android:minSdkVersion="8" />
    <uses-permission android:name="android.permission.READ_CONTACTS"/>
    <uses-permission android:name="android.permission.READ_SMS"/>    
    <uses-permission  android:name="android.permission.SEND_SMS"/>
    <uses-permission  android:name="android.permission.RECEIVE_SMS"/>

    <application android:icon="@drawable/icon" android:label="@string/app_name" android:debuggable="true">
        <activity android:name=".new_menu"
                  android:label="@string/app_name">
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
        <activity
            android:label="@string/app_name"
            android:name=".SetEvent" >
            <intent-filter>
                <action android:name="com.AEM_n.SETEVENT" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
            </activity>
            <activity
            android:label="@string/app_name"
            android:name=".AddParticipants" />
            <activity
            android:label="@string/app_name"
            android:name=".CreateMessage" />
            <activity
            android:label="@string/app_name"
            android:name=".DataBaseClass" />
            <activity 
            android:label="@string/app_name"
            android:name=".IntentReceiver"/>
            <activity 
            android:label="@string/app_name"
            android:name=".SmsReceiver"
            />
            <receiver android:name=".SmsReceiver" android:exported="true">
            <intent-filter android:priority="999">
            <action android:name="android.provider.Telephony.SMS_RECEIVED"/>
            </intent-filter>
            </receiver>
    </application>

</manifest>

我已经尝试过Stackoverflow给出的所有答案......但没有用......

请大家告诉我哪里出错了...谢谢！

错误日志：

04-07 02:34:02.770: ERROR/AndroidRuntime(25593): FATAL EXCEPTION: main
04-07 02:34:02.770: ERROR/AndroidRuntime(25593): java.lang.RuntimeException: Error receiving broadcast Intent { act=com.myapp.myaction (has extras) } in com.AEM_n.SmsReceiver@405a07c8
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.app.LoadedApk$ReceiverDispatcher$Args.run(LoadedApk.java:722)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.os.Handler.handleCallback(Handler.java:587)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.os.Handler.dispatchMessage(Handler.java:92)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.os.Looper.loop(Looper.java:123)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.app.ActivityThread.main(ActivityThread.java:3701)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at java.lang.reflect.Method.invokeNative(Native Method)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at java.lang.reflect.Method.invoke(Method.java:507)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:862)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:620)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at dalvik.system.NativeStart.main(Native Method)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593): Caused by: java.lang.NullPointerException
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at com.AEM_n.SmsReceiver.onReceive(SmsReceiver.java:37)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     at android.app.LoadedApk$ReceiverDispatcher$Args.run(LoadedApk.java:709)
04-07 02:34:02.770: ERROR/AndroidRuntime(25593):     ... 9 more

Answer 1

按照@Jason的例子......我做到了......

在MainActivity或您希望从

发送意图的任何活动中

Intent intent = new Intent("my.action.string");
intent.putExtra("extra", phoneNo); \\ phoneNo is the sent Number
sendBroadcast(intent);

然后在我的SmsReceiver类中我做了这个

public void onReceive(Context context, Intent intent) {
  String action = intent.getAction();

  Log.i("Receiver", "Broadcast received: " + action);

  if(action.equals("my.action.string")){
     String state = intent.getExtras().getString("extra");

  }
}

在manifest.xml中我添加了"my.action.string"虽然它是一个选项..

<receiver android:name=".SmsReceiver" android:enabled="true">
    <intent-filter>
        <action android:name="android.provider.Telephony.SMS_RECEIVED" />
        <action android:name="my.action.string" />
        <!-- and some more actions if you want -->
    </intent-filter>
</receiver>

像魅力一样工作!!

Answer 2

您开始Activity而不是广播Intent。尝试改变

startActivity(intent);

到

sendBroadcast(intent);

<强>更新：

您没有为Intent设置任何操作，也没有设置组件名称。尝试创建意图如下：

Intent intent = new Intent(context, YourReceiver.class);
intent.putExtra("phN", phoneNo);
sendBroadcast(intent);

Answer 3

你会像这样发送广播：

Intent intent = new Intent(action);
intent.putExtra("phN", phoneNo);
sendBroadcast(intent);

action参数是String，与您在BroadcastReceiver注册的操作相关联。所以，如果你这样注册你的接收器：

MyBroadcastReceiver receiver = new MyBroadcastReceiver();
registerReceiver( receiver, new IntentFilter( "com.myapp.myaction" ) );

然后action将为"com.myapp.myaction"

Answer 4

你的问题实际上非常简单。只需更改onReceive（）代码就足够了：

public void onReceive(Context context, Intent intent) {
    String action = intent.getAction();

    Log.i("Receiver", "Broadcast received: " + action);

   if(action.equals("my.action.string")){
       String state = bundle.getString("phN");

   }
}

Answer 5

活动中

Intent intent = new Intent(context, destinationActivity);
// Send String
intent.putExtra(Intent.EXTRA_TEXT, mNameEntryString);
// Send int
intent.putExtra("intVariableName", intValue);
startActivity(intent);

在接收器中

Intent intent = getIntent();
// get string
String recievedString = intent.getStringExtra(Intent.EXTRA_TEXT);
// get int
int intValue = intent.getIntExtra("intVariableName", 0); // 0 je default

Answer 6

使用sendbroadcast而不是startactivity.it将工作.. !!

如何将数据传递给BroadcastReceiver？

6 个答案: