Question

我想打印这样的东西（一个7天的日历），但能够从我想要的任何日期开始。

Monday, 1 January 2011
Tuesday, 2 January 2011
Wednesday, 3 January 2011
Thursday, 4 January 2011
Friday, 5 January 2011
Saturday, 6 January 2011
Sunday, 7 January 2011

例如，我希望从2月22日开始接下来的七天。不知道如何处理这个问题。

Answer 1

这似乎就是你要找的东西：

function GetDates(startDate, daysToAdd) {
    var aryDates = [];

    for (var i = 0; i <= daysToAdd; i++) {
        var currentDate = new Date();
        currentDate.setDate(startDate.getDate() + i);
        aryDates.push(DayAsString(currentDate.getDay()) + ", " + currentDate.getDate() + " " + MonthAsString(currentDate.getMonth()) + " " + currentDate.getFullYear());
    }

    return aryDates;
}

function MonthAsString(monthIndex) {
    var d = new Date();
    var month = new Array();
    month[0] = "January";
    month[1] = "February";
    month[2] = "March";
    month[3] = "April";
    month[4] = "May";
    month[5] = "June";
    month[6] = "July";
    month[7] = "August";
    month[8] = "September";
    month[9] = "October";
    month[10] = "November";
    month[11] = "December";

    return month[monthIndex];
}

function DayAsString(dayIndex) {
    var weekdays = new Array(7);
    weekdays[0] = "Sunday";
    weekdays[1] = "Monday";
    weekdays[2] = "Tuesday";
    weekdays[3] = "Wednesday";
    weekdays[4] = "Thursday";
    weekdays[5] = "Friday";
    weekdays[6] = "Saturday";

    return weekdays[dayIndex];
}

var startDate = new Date();
var aryDates = GetDates(startDate, 7);
console.log(aryDates);

结果（截至今天）：

["Thursday, 5 April 2012",
 "Friday, 6 April 2012", 
 "Saturday, 7 April 2012", 
 "Sunday, 8 April 2012", 
 "Monday, 9 April 2012", 
 "Tuesday, 10 April 2012", 
 "Wednesday, 11 April 2012", 
 "Thursday, 12 April 2012"]

这是a working fiddle。

Answer 2

初始日期：

var startingDay = new Date(year, month, day);

startingDay整整一周：

var thisDay = new Date();
for(var i=0; i<7; i++) {
  thisDay.setDate(startingDay.getDate() + i);
  console.log(thisDay.format());
}

格式化功能：

Date.prototype.format = function(){
    var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];        
    var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
    return days[this.getDay()]
          +", "
          +this.getDate()
          +" "
          +months[this.getMonth()] 
          +" "
          +this.getFullYear();
};

Answer 3

以下是使用Moment.js

的解决方案

接下来的7天

let days = [];
let daysRequired = 7

for (let i = 1; i <= daysRequired; i++) {
  days.push( moment().add(i, 'days').format('dddd, Do MMMM YYYY') )
}

console.log(days)

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>

万一您需要前7天

let days = [];
let daysRequired = 7

for (let i = daysRequired; i >= 1; i--) {
  days.push( moment().subtract(i, 'days').format('dddd, Do MMMM YYYY') )
}

console.log(days)

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>

Answer 4

var feb22 = new Date(2012, 1, 22);
var feb23 = new Date(feb22.getTime() + 1000*60*60*24);

......等等

Answer 5

您可以将变量dateString设置为您想要的任何值，并且在循环中您只需增加日期。然后你会得到日期，但我想以不同的格式。

var dateString = '22 Feb 2012';
var actualDate = new Date(dateString);
var newDate;

for(var i=1; i<=7; i++){
 newDate = new Date(actualDate.getFullYear(), actualDate.getMonth(), actualDate.getDate()+i);
}

Answer 6

如果从今天开始需要接下来的7个工作日

＆＃13;

#include <iostream>
#include <string>
#include <math.h>
#include <iomanip>

bool isPerfect(int n);
using namespace std;

int main() {
    long long perfect = 0;
    int first = 0;

    first = (pow(2, 2 - 1))*(pow(2, 2) - 1);
    cout << first << endl;
    for (int i = 3, j = 1; j < 5; i += 2) {
        if (isPerfect(i)) {
            perfect = (pow(2, i - 1)*(pow(2, i) - 1));
            cout << perfect << endl;
            j++;
        }
    }




    // pause and exit
    getchar();
    getchar();
    return 0;
}
bool isPerfect(int n)
{
    if (n < 2) {
        return false;
    }
    else if (n == 2) {
        return true;
    }
    else if (n % 2 == 0) {
        return false;
    }
    else {
        bool prime = true;
        for (int i = 3; i < n; i += 2) {
            if (n%i == 0) {
                prime = false;
                break;
            }
        }
        return prime;
    }
}

＆＃13;

const isWeekday = (date) => {
	return date.weekday()!==0 && date.weekday()!==6
}

const weekdays=[];
let numberOfDaysRequired = 7
let addDaysBy = 1
moment.locale('en')
while(weekdays.length < numberOfDaysRequired)
{
  const d = moment().add(addDaysBy, 'days')
  if(isWeekday(d))
  {
  	weekdays.push(d.format('dddd, Do MMMM YYYY'))
  	
  }
  addDaysBy++;
}

console.log(weekdays)

＆＃13;

如何从X获取接下来的七天并在JS中进行格式化

6 个答案: