我在视图中使用向导步骤,我的项目在MVC3上。
我有一个3个步骤的表单,这意味着我的表单中的每个步骤都有三个标签 和以下两个按钮:
<p><input type="button" id="next-step" class="next-step-client-val" name="next-step" value="Next" /></p><
<p><input type="button" value="Back id="back-step" name="back-step"></p>
在我的第一步中,我只有一堆TextBoxes
,DropDownlists
和TextAreas
,第二步有很多客户端功能,一个例子是用户可以从中移动行一个表到另一个等等。我有一个Jquery验证,如下:
var customTbl = $('#CustomPickedTable');
var has1 = customTbl.find('td[data-row="1"]').is('*');
var has2 = customTbl.find('td[data-row="2"]').is('*');
var has3 = customTbl.find('td[data-row="3"]').is('*');
var has4 = customTbl.find('td[data-row="4"]').is('*');
if ((has1 === true) && (has2 === true) && (has3 === true) && (has4 === true)) {
jAlerts("Saved", "Info");
} else {
jAlert('You have to move atleast one row from each table', "Varning"); ;
return false
}
在第3步,当用户点击它时,它只是审查创建的内容和我的下一步按钮提交表单。
我希望能够做到的是当用户处于第2步并点击下一步按钮时,上面的jquery验证应该运行。使用我的向导步骤代码,我无法做到这一点,因为它使用下一步按钮选择器的一切。对此有什么解决方案吗?
我试图将我的Jquery验证码放在
中$("#next-step").click(function () {
}
但是每当用户点击下一个按钮时,我的jquery验证代码就会运行,因为我的表格显示在表单中但是隐藏了,当用户点击下一步时,验证会在第一步触发。所以这个解决方案没有用。
这是我的向导步骤Jquery代码,现在我在底部进行了Jquery验证,这意味着当我在第3步并单击下一步按钮时,它将验证然后发布。但我不希望它像那样。我希望验证在第2步发生。
以下是代码:
$(function () {
$(".wizard-step:first").fadeIn(); // show first step
// attach backStep button handler
// hide on first step
$("#back-step").hide().click(function () {
var $step = $(".wizard-step:visible"); // get current step
if ($step.prev().hasClass("wizard-step")) { // is there any previous step?
$step.hide().prev().fadeIn(4500); // show it and hide current step
// disable backstep button?
if (!$step.prev().prev().hasClass("wizard-step")) {
$("#back-step").hide();
}
}
});
// attach nextStep button handler
$("#next-step").click(function () {
var $step = $(".wizard-step:visible"); // get current step
var validator = $("form").validate(); // obtain validator
var anyError = false;
$step.find("select").each(function () {
if (!this.disabled && !validator.element(this)) { // validate every input element inside this step
anyError = true;
}
});
$step.find("input").each(function () {
if (!validator.element(this)) { // validate every input element inside this step
anyError = true;
}
});
$("#next-step").click(function () {
if (!validator.element(this)) { // validate every input element inside this step
anyError = true;
}
});
if (anyError)
return false; // exit if any error found
if ($step.next().hasClass("confirm")) { // is it confirmation?
// show confirmation asynchronously
$.post("/wizard/confirm", $("form").serialize(), function (r) {
// inject response in confirmation step
$(".wizard-step.confirm").html(r);
});
}
if ($step.next().hasClass("wizard-step")) { // is there any next step?
$step.hide().next().fadeIn(4500); // show it and hide current step
$("#back-step").show(); // recall to show backStep button
}
else { // this is last step, submit form
var selectedQuestions = $("#SelectedQuestions");
var selectedCustomQuestions = $("#SelectedCustomQuestions");
var currentIds = new Array();
var currentText = new Array();
$("#CustomPickedTable td[data-question-id]").each(function () {
var clickedId = $(this).attr("data-question-id");
currentIds.push(clickedId);
});
$('#CustomPickedTable td[data-attr-id]').each(function () {
var ClickedText = $(this).html();
currentText.push(ClickedText);
});
selectedCustomQuestions.val(currentText.join("|"));
selectedQuestions.val(currentIds.join(","));
var customTbl = $('#CustomPickedTable');
var has1 = customTbl.find('td[data-row="1"]').is('*');
var has2 = customTbl.find('td[data-row="2"]').is('*');
var has3 = customTbl.find('td[data-row="3"]').is('*');
var has4 = customTbl.find('td[data-row="4"]').is('*');
if ((has1 === true) && (has2 === true) && (has3 === true) && (has4 === true)) {
jAlerts("saved", "Info");
} else {
jAlert('You have to move atleast one row from each table', "Varning"); ;
}
return false;
}
});
我的HTML代码看起来像这样:
<div class="wizard-step>
//step 1 content
</div>
<div class="wizard-step>
//step 2 content
</div>
<div class="wizard-step>
//step 3 content
</div>
<p><input type="button" id="next-step" class="next-step-client-val" name="next-step" value="Next" /></p><
<p><input type="button" value="Back id="back-step" name="back-step"></p>
答案 0 :(得分:2)
我认为如果您使用jquery .index()函数检测到哪个向导步骤会更好。这样,只有在第二步进入第三步时,才能在下一步单击处理程序中进行验证。代码看起来像这样:
$("#next-step").click(function () {
var $step = $(".wizard-step:visible"); // get current step
var stepIndex = $(".wizard-step").index($step); //index returns 0 based index so second step would be 1.
var validator = $("form").validate(); // obtain validator
var anyError = false;
$step.find("select").each(function () {
if (!this.disabled && !validator.element(this)) { // validate every input element inside this step
anyError = true;
}
});
$step.find("input").each(function () {
if (!validator.element(this)) { // validate every input element inside this step
anyError = true;
}
});
if (anyError)
return false; // exit if any error found
if(stepIndex == 1) //if you are on second step then validate your table
{
var customTbl = $('#CustomPickedTable');
var has1 = customTbl.find('td[data-row="1"]').is('*');
var has2 = customTbl.find('td[data-row="2"]').is('*');
var has3 = customTbl.find('td[data-row="3"]').is('*');
var has4 = customTbl.find('td[data-row="4"]').is('*');
if ((has1 === true) && (has2 === true) && (has3 === true) && (has4 === true)) {
jAlerts("Saved", "Info");
} else {
jAlert('You have to move atleast one row from each table', "Varning"); ;
return false
}
}
else if ($step.next().hasClass("confirm")) { // is it confirmation?
// show confirmation asynchronously
$.post("/wizard/confirm", $("form").serialize(), function (r) {
// inject response in confirmation step
$(".wizard-step.confirm").html(r);
});
}
if ($step.next().hasClass("wizard-step")) { // is there any next step?
$step.hide().next().fadeIn(4500); // show it and hide current step
$("#back-step").show(); // recall to show backStep button
}
else { // this is last step, submit form
var selectedQuestions = $("#SelectedQuestions");
var selectedCustomQuestions = $("#SelectedCustomQuestions");
var currentIds = new Array();
var currentText = new Array();
$("#CustomPickedTable td[data-question-id]").each(function () {
var clickedId = $(this).attr("data-question-id");
currentIds.push(clickedId);
});
$('#CustomPickedTable td[data-attr-id]').each(function () {
var ClickedText = $(this).html();
currentText.push(ClickedText);
});
}
});
答案 1 :(得分:1)
我认为你可以通过重构代码来解决这个问题
// validate the inputs in a form
// @param {string|object} jquery selector or jquery object
function validateStep (selector){
var $step = $(selector);
var validator = $("form").validate();
var anyError = false;
$step.find("select").each(function () {
if (!this.disabled && !validator.element(this)) {
anyError = true;
}
$step.find("input").each(function () {
if (!validator.element(this)) {
anyError = true;
}
if (!validator.element(this)) {
anyError = true;
}
return anyError;
}
这样您就可以通过调用
来验证第二步// this works because jquery returns an array of objects
// as a result of the css selector we call it with
// the eq() function accepts an index value that returns
// the jquery object at that position
// see. http://api.jquery.com/eq-selector/
validateStep($('.wizard-step').eq(1));
或第一个
validateStep('.wizard-step:first');
等
我们可以将此合并到您的代码中 -
$('#next-step').click(function (event){
var $step = $('.wizard-step');
if(validateStep($step.filter(':visible'))){
// go to the next step
if ($step.next().hasClass("wizard-step")) {
$step.hide().next().fadeIn(4500);
$("#back-step").show();
} else {
// submit form
}
}
});
注意:您可以在此处阅读有关jQuery选择器的更多信息http://api.jquery.com/category/selectors/