Question

如果您有电子邮件地址

you.late.you@asdf.com

you_late_you@asdf.com

如果使用sql代码有2个点/下划线，如何计算？

Answer 1

select len('you.late.you@asdf.com') - len(replace('you.late.you@asdf.com', '.', ''))

Answer 2

这将为您提供所需的结果。

 DECLARE @str VARCHAR(1000)
SET @str = 'you.l_ate.you@as_df.com'
SELECT (LEN(@str)- LEN(REPLACE(@str ,'.' ,'')))+(LEN(@str)- LEN(REPLACE(@str ,'_' ,'')))

回答：5

Answer 3

我想他想在@：

之前计算没有点的字母

declare @myEmail varchar(50)
set @myEmail = 'you.late.you@asdf.com'

declare @mySearch varchar(50)
set @mySearch = SUBSTRING (@myEmail,0 , PATINDEX( '%@%',@myEmail))
select (LEN(REPLACE(@mySearch, '.', '')))

Answer 4

如果要计算包含两个.或_的行数，可以执行以下操作：

select count(*) 
  from mytable 
 where left(email, charindex('@', email)) like '%[._]%[._]%'

left和charindex用于忽略域名（具有.）。

参考：LIKE (TSQL, SQL Server 2008)

Answer 5

select 
    length(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1))) - 
    length(replace(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1)), '.', '')) 
from dual

计算SQL字符串值中字符出现次数？

5 个答案: