我从HttpGet返回数据,然后使用适配器将字符串传递给Listview。问题是,在我将数据返回到字符串后,Eclipse不允许我返回数据。
错误:Void方法无法返回值。
代码:
public class ChatService extends ListActivity {
/** Called when the activity is first created. */
BufferedReader in = null;
String data = null;
List headlines;
List links;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
try {
ContactsandIm();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
CheckLogin();
}
private void CheckLogin() {
// TODO Auto-generated method stub
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
/* login.php returns true if username and password is equal to saranga */
HttpPost httppost = new HttpPost("http://gta5news.com/login.php");
try {
// Execute HTTP Post Request
Log.w("HttpPost", "Execute HTTP Post Request");
HttpResponse response = httpclient.execute(httppost);
String str = inputStreamToString(response.getEntity().getContent())
.toString();
Log.w("HttpPost", str);
if (str.toString().equalsIgnoreCase("true")) {
Log.w("HttpPost", "TRUE");
try {
Thread.sleep(250);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// put intent here(21/3/12);
} else {
Log.w("HttpPost", "FALSE");
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private StringBuilder inputStreamToString(InputStream is) {
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
// Read response until the end
try {
while ((line = rd.readLine()) != null) {
total.append(line);
}
} catch (IOException e) {
e.printStackTrace();
}
// Return full string
return total;
}
public void ContactsandIm() throws URISyntaxException,
ClientProtocolException, IOException {
headlines = new ArrayList();
// TODO Auto-generated method stub
BufferedReader in = null;
String data = null;
HttpClient get = new DefaultHttpClient();
URI website = new URI("http://www.gta5news.com/test.php");
HttpGet webget = new HttpGet();
webget.setURI(website);
HttpResponse response = get.execute(webget);
Log.w("HttpPost", "Execute HTTP Post Request");
in = new BufferedReader(new InputStreamReader(response.getEntity()
.getContent()));
StringBuffer sb = new StringBuffer("");
String l ="";
String nl = System.clearProperty("line.seperator");
while ((l =in.readLine()) !=null) {
sb.append(l + nl);
}
in.close();
data = sb.toString();
return data;
headlines.add(sb);
ArrayAdapter adapter = new ArrayAdapter(this,
android.R.layout.simple_list_item_1, headlines);
setListAdapter(adapter);
}
// end bracket for "ContactsandIm"
}
答案 0 :(得分:1)
您无法使用void
方法返回任何内容。如果您希望返回ContactsandIm()
,则需要将返回类型添加到String
类型的String
。此外,调用return x
将退出该方法,因此返回后的任何代码都是死代码。
答案 1 :(得分:1)
在您ContactsAndIm
之后的data = sb.toString();
函数return data;
正在进行{{1}}摆脱它,你应该没问题。它不是eclipse,它是java编译器告诉你不能在带有void签名的函数中返回一个值