带有多个表和SUM的SQL SELECT

时间:2012-04-04 18:23:07

标签: sql select

我已经使用这个论坛一段时间来找到一些SQL相关问题的答案。现在是时候提出一个我试图弄清楚的问题了。

我有两张桌子(产品和来源)。

我想创建一个SQL SELECT来从源中检索记录列表,从产品中检索一个额外的记录(价格的总和)。我希望看到的表应该是这样的:

source.source_id | source.location | source.source_name | source.source_description | source.source_date | source.price | SUM(product.price)| SUM(product.price)WHERE product.quantity< 1(最后一栏是我被卡住的地方)。

source.location和product.location是链接的。

此代码有效并提供我想要的结果:

SELECT s.source_id
    , s.location
    , s.source_name
    , s.source_description
    , s.source_date
    , s.source_price
    , p2.Total
    , sum(p1.price) as SumProductSold
FROM source s
JOIN product p1
    on s.location = p1.location
JOIN
(
    SELECT location, sum(price) as Total
    FROM product
    GROUP BY location
) p2
    on s.location = p2.location
WHERE p1.quantity < 1
GROUP BY s.source_id, s.location, s.source_name
    , s.source_description, s.source_date, s.source_price, p2.Total

谢谢bluefeet !!

3 个答案:

答案 0 :(得分:4)

没有很多细节你可以做这样的事情:

SELECT s.source_id
    , s.location
    , s.source_name
    , s.source_description
    , s.source_date
    , s.price
    , sum(p.price) as SumProductPrice
    , sum(p.location) as SumProductLocation
FROM source S
JOIN product p
    on S.location = p.location
WHERE p.quantity < 1
GROUP BY s.source_id, s.location, s.source_name
    , s.source_description, s.source_date, s.price

如果您发布更多详细信息,则可以对查询进行微调。

编辑:

您可以再次加入产品表以获取该位置的总数:

SELECT s.source_id
    , s.location
    , s.source_name
    , s.source_description
    , s.source_date
    , s.price
    , sum(p1.price) as SumProductPrice
    , p2.Total
FROM source S
JOIN product p1
    on S.location = p1.location
JOIN
(
    SELECT location, sum(price) as Total
    FROM product
    WHERE quantity < 1
    GROUP BY location
) p2
    on S.location = p2.location
WHERE p1.quantity < 1
GROUP BY s.source_id, s.location, s.source_name
    , s.source_description, s.source_date, s.price, p2.Total

答案 1 :(得分:0)

我不确定我是否完全理解你的表格结构,但这样的事情应该有效:

Select source.source_id, 
  source.location, 
  source.source_name, 
  source.source_description,
  source.source_date,
  source.price,
  sum(production.location)
from source, product
  where source.location = production.location
  and location < 0
group by source.source_id, 
  source.location, 
  source.source_name, 
  source.source_description,
  source.source_date,
  source.price

答案 2 :(得分:0)

从我收集的内容中你想要这样的东西:

SELECT  source.source_id,
        source.location,
        source.source_name,
        source.source_description,
        source.source_date,
        source.price,
        SUM(product.price) AS Price1,
        SUM(CASE WHEN product.quantity < 1 THEN product.price ELSE 0 END)  AS Price2
FROM    Source
        INNER JOIN Product
            ON Product.Location = Source.Location
GROUP BY 
        source.source_id,
        source.location,
        source.source_name,
        source.source_description,
        source.source_date,
        source.price