Question

我无法将SQL Select语句输出到我的XML以用于我的Graph

我有这些结果

December 2011 470 FRESENIUS

January 2012 434 FRESENIUS

February 2012 278 FRESENIUS

February 2012 2 STORESID

我需要像这样输出它们，这样我就可以循环我的代码并生成XML

Month Year FRESNIUS STORESID

December 2011 470 0

January 2012 434 0

February 2012 278 2

请注意我没有包含标题，这些都是列结果。此外，STORESID和FRESNIUS不是静态价值观。多个存储器存在，因此我还需要动态扩展我的列数。

我有点需要输出第二个来通过PHP正确生成XML，我已经拥有了。还是有其他正确的方式。

感谢。

在下面查询我正在讨论的输出

SELECT  
        DATENAME(month, orderdate)  + ' ' + CAST(Year(orderdate) AS VARCHAR(4)) AS 'Month Year' ,
        count(*) 'Number of Orders', 
        storerkey
FROM    orders
GROUP BY
        storerkey,
        DATENAME(month, orderdate) + ' ' +  CAST(Year(orderdate) AS VARCHAR(4)),
        CAST(Year(orderdate) AS VARCHAR(4)) + RIGHT('0' + CAST(Month(orderdate) AS VARCHAR(2)),2)
ORDER BY    
        storerkey,
        CAST(Year(orderdate) AS VARCHAR(4)) + RIGHT('0' + CAST(Month(orderdate) AS VARCHAR(2)),2)

Answer 1

您可以将表格加入到自身中。如果我对列名做出假设，假设可能缺少FRESNIUS或STORESID，并使用公用表表达式（未经测试！）：

WITH date_fresnius AS (
    SELECT [Month Year], FRESNIUS
    FROM original_table
)
, date_storesid AS (
    SELECT [Month Year], STORESID
    FROM original_table
)
SELECT
      ISNULL( f.[Month Year], s.[Month Year]) AS [Month Year]
    , ISNULL( f.FRESNIUS, 0 ) AS FRESNIUS
    , ISNULL( s.STORESID, 0 ) AS STORESID
FROM
    date_fresnius f
    FULL OUTER JOIN date_storesid s ON (f.[Month Year] = s.[Month Year])

如果您总是拥有FRESNIUS记录，则可以使用LEFT JOIN。

Answer 2

我不是100％确定您需要的XML输出，但您可以利用SQL-Servers FOR XML clause和PIVOT功能。这应该让你开始：

CREATE TABLE #Test (GraphDate DATETIME, Value INT, Type VARCHAR(50))
INSERT #Test VALUES 
    ('01/12/2011', 470, 'FRESENIUS'),
    ('01/01/2012', 434, 'FRESENIUS'),
    ('01/12/2012', 278, 'FRESENIUS'),
    ('01/02/2012', 2, 'STORESID')

SELECT  DATEPART(YEAR, GraphDate) [Year], 
        DATENAME(MONTH, GraphDate) [Month], 
        ISNULL(FRESENIUS, 0) [FRESENIUS],
        ISNULL(STORESID, 0) [STORESID]
FROM    #Test
        PIVOT
        (   SUM(Value)
            FOR Type IN ([FRESENIUS], [STORESID])
        ) PivotTable
FOR XML PATH('row'), ROOT

DROP TABLE #Test

修改

以下是您根据您提供的查询要求的基本查询。

SELECT DATENAME(MONTH, OrderDate) + ' ' + DATENAME(YEAR, OrderDate) [MonthYear], ISNULL(FRESENIUS, 0) [FRESENIUS], ISNULL(STORESID, 0) [STORESID] FROM Orders PIVOT ( COUNT(StorerKey) FOR StorerKey IN ([FRESENIUS], [STORESID]) ) PivotTable ORDER BY DATEPART(YEAR, OrderDate), DATEPART(MONTH, OrderDate)

编辑2

我认为SQL-Server 2000不支持PIVOT。您需要使用聚合函数：

SELECT DATENAME(MONTH, OrderDate) + ' ' + DATENAME(YEAR, OrderDate) [MonthYear], COUNT(CASE WHEN StorerKey = 'FRESENIUS' THEN 1 END) [FRESENIUS], COUNT(CASE WHEN StorerKey = 'STORESID' THEN 1 END) [STORESID] FROM Orders GROUP BY DATEPART(YEAR, OrderDate), DATEPART(MONTH, OrderDate), DATENAME(YEAR, OrderDate), DATENAME(MONTH, OrderDate) ORDER BY DATEPART(YEAR, OrderDate), DATEPART(MONTH, OrderDate)

我认为某些FOR XML功能仍然可用，因此您仍然可以直接从SQL输出XML。

编辑3

DECLARE @SQL NVARCHAR(2000) SELECT @SQL = ISNULL(@SQL, '') + ', COUNT(CASE WHEN StorerKey = ''' + StorerKey + ''' THEN 1 END) [' + StorerKey + ']' FROM ( SELECT DISTINCT StorerKey FROM Orders ) Keys SET @SQL = 'SELECT DATENAME(MONTH, OrderDate) + '' '' + DATENAME(YEAR, OrderDate) [MonthYear]' + @SQL + ' FROM Orders GROUP BY DATEPART(YEAR, OrderDate), DATEPART(MONTH, OrderDate), DATENAME(YEAR, OrderDate), DATENAME(MONTH, OrderDate) ORDER BY DATEPART(YEAR, OrderDate), DATEPART(MONTH, OrderDate)' EXECUTE SP_EXECUTESQL @SQL

Answer 3

根据您的查询：

SELECT
    DATENAME(MONTH, orderdate) + ' ' + CAST(YEAR(orderdate) AS VARCHAR(4)) AS [Month Year]
    COUNT(CASE storerkey WHEN 'FRESNIUS' THEN 1 END) AS FRESNIUS,
    COUNT(CASE storerkey WHEN 'STORESID' THEN 1 END) AS STORESID
FROM orders
GROUP BY YEAR(orderdate), MONTH(orderdate), DATENAME(MONTH, orderdate)
ORDER BY YEAR(orderdate), MONTH(orderdate)

输出：

Month Year      FRESNIUS   STORESID
December 2011        470          0
January 2012         434          0
February 2012        278          2

SIMPLE SQL SELECT INTO GRAPH

3 个答案: