所以最开始是按钮的问题,只是意味着我的文件存在问题。我想将数字保存到我的文件中,还有我选择的languege。 languege工作得很完美,但当我尝试对我的数字做同样的事情时,它就出错了
所以这是我的languege文件的代码
french.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
try{
buttonSound.start();
String FILENAME = "LangFile";
String data ="FR";
FileOutputStream fos = openFileOutput(FILENAME, Context.MODE_PRIVATE);
fos.write(data.getBytes());
fos.close();
FILENAME="TempFile";
data="0";
FileOutputStream fostemp = openFileOutput(FILENAME, Context.MODE_PRIVATE);
fostemp.write(data.getBytes());
fostemp.close();
startActivity(new Intent("com.technopolisapp.LOGOTECHNOPOLIS"));
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
finally{
finish();
}
}
});
这里我为按下的按钮保存了2个字母 这是再次读取它的代码,并使选择了languege的按钮
try{
String FILENAME = "LangFile";
FileInputStream fos = openFileInput(FILENAME);
byte[] b = new byte[2];
fos.read(b);
fos.close();
if(new String(b).equalsIgnoreCase("NL")){
Tower.setText(classNamesDutch[0]);
Puzzle.setText(classNamesDutch[1]);
Mirror.setText(classNamesDutch[2]);
Tangram.setText(classNamesDutch[3]);
Frog.setText(classNamesDutch[4]);
}
if(new String(b).equalsIgnoreCase("GB")){
Tower.setText(classNamesEnglish[0]);
Puzzle.setText(classNamesEnglish[1]);
Mirror.setText(classNamesEnglish[2]);
Tangram.setText(classNamesEnglish[3]);
Frog.setText(classNamesEnglish[4]);
}
if(new String(b).equalsIgnoreCase("FR")){
Tower.setText(classNamesFrench[0]);
Puzzle.setText(classNamesFrench[1]);
Mirror.setText(classNamesFrench[2]);
Tangram.setText(classNamesFrench[3]);
Frog.setText(classNamesFrench[4]);
}
}catch (java.io.FileNotFoundException e) {
} catch (IOException e) {
e.printStackTrace();
}
现在这是我保存和阅读我的号码的代码
public void Savefile(){
int level=0;
String data;
try{
String FILENAME = "TowerFile";
FileInputStream fos = openFileInput(FILENAME);
byte[] b = new byte[1];
fos.read(b);
fos.close();
if(new String(b).equalsIgnoreCase("1")){
level=1;
}
if(new String(b).equalsIgnoreCase("2")){
level=2;
}
if(new String(b).equalsIgnoreCase("3")){
level=3;
}
if(new String(b).equalsIgnoreCase("4")){
level=4;
}
if(new String(b).equalsIgnoreCase("5")){
level=5;
}
if(level!=1 || level!=2 || level!=3 || level!=4 || level!=5){
FILENAME="TowerFile";
data="een";
FileOutputStream fostemp = openFileOutput(FILENAME, Context.MODE_PRIVATE);
fostemp.write(data.getBytes());
fostemp.close();
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
这就是我想要阅读的方式
try{
String FILENAME = "TowerFile";
FileInputStream fos = openFileInput(FILENAME);
byte[] b = new byte[1];
fos.read(b);
fos.close();
if(new String(b).equalsIgnoreCase("1")){
button1.setVisibility(Button.GONE);
}
if(new String(b).equalsIgnoreCase("2")){
level=2;
}
if(new String(b).equalsIgnoreCase("3")){
level=3;
}
if(new String(b).equalsIgnoreCase("4")){
level=4;
}
if(new String(b).equalsIgnoreCase("5")){
level=5;
}
}catch (java.io.FileNotFoundException e) {
} catch (IOException e) {
e.printStackTrace();
}
所以我现在并没有真正意识到它出错的地方
答案 0 :(得分:0)
您想使用Context.openFileStream(Context.MODE_PRIVATE)。它没有解释为什么你必须这样做,我假设操作系统权限,但这应该适合你。