Question

从两个不同的select语句中保存两个值的最佳和简单方法是什么？

我的查询是这样的：

SELECT * FROM (
SELECT FIELD1 FROM (<SUB SELECT STATMENT>)
UNION ALL
SELECT FIELD2 FROM (<SUB SELECT STATMENT>))

我想要的是保存FIELD1和FIELD2的值，以便稍后我可以用它做一些计算，比如FIELD1 / FIELD2。我尝试使用游标但遇到了问题。对于select语句来说太复杂了。有什么建议吗？

更新：

我当前查询的结果集如下所示。

SUM_OF_MESSAGES  | LABEL
----------------------------
      145323     | PUSHED
      2633267    | RECEIVED
                 |

我想从前两行中取出值并将它们分开。例如。 145323/2633267

换句话说，有没有办法将FIELD1除以上面的查询中的FIELD2？

另一个更新：

这是我的问题：

SELECT SUM(R.MESSAGES) AS SUM_OF_MESSAGES, CASE WHEN R.LABEL = 1 THEN 'PUSHED' WHEN R.LABEL = 2 THEN 'RECEIVED' END AS LABEL FROM (                
SELECT SUM(Q.MESSAGES) AS "MESSAGES", 1 LABEL FROM (
SELECT USER_LOGIN,
                 EVENT_MSG,
                 ROW_LST_UPD_TS,
                 COMPONENT_NAME,
                 REGEXP_SUBSTR (SUBSTR (EVENT_MSG, INSTR (EVENT_MSG, ' ', 1, 1), INSTR (EVENT_MSG, ' ', 1, 1)), '[0-9]+') AS "MESSAGES"
            FROM EVENT_MGT.EVENT_LOG
            WHERE ROW_LST_UPD_TS BETWEEN (TRUNC (:DATEINPUT) - 1) + 5 / 86400 AND (TRUNC (:DATEINPUT)) + 5 / 86400
                 AND EVENT_ID = 101
                 AND COMPONENT_NAME LIKE '%Web ICE Downloader.exe%'
        GROUP BY COMPONENT_NAME,
                 USER_LOGIN,
                 EVENT_MSG,
                 ROW_LST_UPD_TS
                 ORDER BY ROW_LST_UPD_TS ) Q         
UNION ALL           
SELECT SUM(Q.MESSAGES) "MESSAGES", 2 LABEL FROM (
SELECT USER_LOGIN,
                 EVENT_MSG,
                 ROW_LST_UPD_TS,
                 COMPONENT_NAME,
                 REGEXP_SUBSTR (SUBSTR (EVENT_MSG, INSTR (EVENT_MSG, ' ', 1, 1), INSTR (EVENT_MSG, ' ', 1, 1)), '[0-9]+') AS "MESSAGES"
            FROM EVENT_MGT.EVENT_LOG
            WHERE ROW_LST_UPD_TS BETWEEN (TRUNC (:DATEINPUT) - 1) + 5 / 86400 AND (TRUNC (:DATEINPUT)) + 5 / 86400
                 AND EVENT_ID = 100
                 AND COMPONENT_NAME LIKE '%Web ICE Downloader.exe%'
        GROUP BY COMPONENT_NAME,
                 USER_LOGIN,
                 EVENT_MSG,
                 ROW_LST_UPD_TS
                 ORDER BY ROW_LST_UPD_TS ) Q ) R
                 GROUP BY  R.LABEL

这是我的结果集：

SUM_OF_MESSAGES  | LABEL
----------------------------
      145323     | PUSHED
      2633267    | RECEIVED
                 |

我想在同一个select语句中将这两个数字分开。请帮忙。

Answer 1

您的聚合似乎只需要一个带有一点逻辑的查询

      SELECT COUNT( CASE WHEN event_id = 100 
                         THEN q.messages
                         ELSE null
                     END) Received,
             COUNT( CASE WHEN event_id = 101
                         THEN q.messages 
                         ELSE null
                     END) Pushed,
             COUNT( CASE WHEN event_id = 101
                         THEN q.messages 
                         ELSE null
                     END) /
                COUNT( CASE WHEN event_id = 100 
                           THEN q.messages
                           ELSE null
                       END) Pushed_Over_Received
        FROM (
          SELECT USER_LOGIN,
                 EVENT_ID,
                 EVENT_MSG,
                 ROW_LST_UPD_TS,
                 COMPONENT_NAME,
                 REGEXP_SUBSTR (SUBSTR (EVENT_MSG, INSTR (EVENT_MSG, ' ', 1, 1), 
                 INSTR (EVENT_MSG, ' ', 1, 1)), '[0-9]+') AS "MESSAGES"
            FROM EVENT_MGT.EVENT_LOG
            WHERE ROW_LST_UPD_TS BETWEEN (TRUNC (:DATEINPUT) - 1) + 5 / 86400 
                                     AND (TRUNC (:DATEINPUT)) + 5 / 86400
              AND EVENT_ID in( 100, 101 )
              AND COMPONENT_NAME LIKE '%Web ICE Downloader.exe%'
        )

或者，您可以使用分析函数执行类似的操作（您希望将查询中的子查询t替换为您编写的产生两行输出的查询。

SQL> ed
Wrote file afiedt.buf

  1  with t as (
  2    select 145323 sum_of_messages, 'PUSHED' label from dual
  3    union all
  4    select 2633267, 'RECEIVED' from dual
  5  )
  6  select sum_of_messages,
  7         label,
  8         round( 100*ratio_to_report(sum_of_messages) over (), 2) pct_of_messages
  9*   from t
SQL> /

SUM_OF_MESSAGES LABEL    PCT_OF_MESSAGES
--------------- -------- ---------------
         145323 PUSHED              5.23
        2633267 RECEIVED           94.77

从两个不同变量中的两个select语句中保存值

1 个答案: