以下代码有效,但我想在声明它时使用自调用函数语法,而不是在最后一行显式调用它:
var ShowMe = function() {
if ($('input:checkbox:checked').length) {
$('#Save').fadeIn('slow');
} else {
$('#Save').hide();
}
};
$('input:checkbox').on('click',ShowMe);
ShowMe();
答案 0 :(得分:2)
您无法在表达式中声明var
,但您可以将其定义放在一个中:
var ShowMe; (ShowMe = function() {
if ($('input:checkbox:checked').length) {
$('#Save').fadeIn('slow');
} else {
$('#Save').hide();
}
})();
$('input:checkbox').on('click',ShowMe);
答案 1 :(得分:2)
请改为尝试:
var ShowMe = function() {
if ($(this).length) { // `this` is the input that was clicked
$('#Save').fadeIn('slow');
} else {
$('#Save').hide();
}
};
$('input:checkbox').on('click', ShowMe).trigger('click');
$('#Save').hide();
$('input:checkbox').on('click', function() {
if(this.checked) { //check if this is checked
$('#Save').show('slow');
}
else if(!($('input[type="checkbox"]:checked').length)) {
//check to see if anything else was checked
$('#Save').hide();
}
});