我想抛出一个例外,说我们的电子邮件地址无效,因为在收到有效的电子邮件地址之前我不想继续。这是我想要做的地方,如果是这样,怎么样?
void Engine_AfterReadRecord(EngineBase engine, FileHelpers.Events.AfterReadEventArgs<UserInfoFromAd> e){
bool isEmailValid = IsEmailValid(e.Record.Email);
if (!isEmailValid){
//I want to throw exception
}
}
答案 0 :(得分:3)
在AfterReadRecord
事件中抛出异常很好,但您需要将ErrorMode
设置为SaveAndContinue
。这告诉引擎将错误保存到Engine.ErrorManager.Errors
并继续导入。导入后,您可以处理错误。
以下是一个示例程序:
[DelimitedRecord("|")]
public class MyClass
{
public string Field1 { get; set; }
public int Field2 { get; set; }
public string Email { get; set; }
}
class Program
{
static void Main(string[] args)
{
var engine = new FileHelperEngine<MyClass>();
engine.AfterReadRecord += new FileHelpers.Events.AfterReadHandler<MyClass>(engine_AfterReadRecord);
engine.ErrorMode = ErrorMode.SaveAndContinue;
// import a record with an invalid Email
MyClass[] validRecords = engine.ReadString("Hello|23|World");
ErrorInfo[] errors = engine.ErrorManager.Errors;
Assert.AreEqual(1, engine.TotalRecords); // 1 record was processed
Assert.AreEqual(0, validRecords.Length); // 0 records were valid
Assert.AreEqual(1, engine.ErrorManager.ErrorCount); // 1 error was found
Assert.That(errors[0].ExceptionInfo.Message == "Email is invalid");
}
static bool IsEmailValid(string email)
{
return false;
}
static void engine_AfterReadRecord(EngineBase engine, FileHelpers.Events.AfterReadEventArgs<MyClass> e)
{
bool isEmailValid = IsEmailValid(e.Record.Email);
if (!isEmailValid)
{
throw new Exception("Email is invalid");
}
}
}
答案 1 :(得分:1)
似乎有什么问题?扔掉它:
if (!isEmailValid)
{
throw new InvalidDataException("Email is not valid.");
}