Question

当用户输入他/她的MerryParentEmail地址时，应该从数据库中获取相应的名称并显示在MerryParentName输入文本框中。我已经尝试过使用ajax，jquery和php这样做了。但是现在，当我使用ajax，jquery和cakephp时，没有显示相应的名称。

警报输出：数据％5BMerryParent％5D％5Bemail％5D = b

有人可以指出我哪里出错吗？谢谢。

default.ctp（布局文件）

<script type="text/javascript">
  $(document).ready(function(){
  $("#MerryParentEmail").keyup(function(){
    //txt=$("#MerryParentEmail").val();
    txt=$("#MerryParentEmail").serialize();
    alert(txt);
    $.post("../merry_parents/getname",txt,function(result){
      $("#MerryParentName").val(result);  
    });
  });
});
 </script>

view.ctp

<?php
echo $this->Session->flash();
//echo $this->Form->create('MerryParent', array('default'=>false));
echo $this->Form->create('MerryParent');

echo '<fieldset>';
echo '<legend>Parent Information</legend>';
echo $this->Form->input('MerryParent.email');
/*if (isset($name))
   echo $this->Form->input('MerryParent.name', array('label'=>'Parent/Guardian Name','value'=>$name));
else*/
   echo $this->Form->input('MerryParent.name', array('label'=>'Parent/Guardian Name'));

echo '</fieldset>';

//echo $this->Form->end('Submit');

 ?>

merry_parents_controller.php

<?php
 class MerryParentsController extends AppController{
public $many_children_flag='false';
var $name='MerryParents';

function beforeFilter()//executed before any controller action logic
{   parent::beforeFilter();
    $this->Security->validatePost=false;  //set to false to completely skip the validation of POST request
        //parent::beforeFilter();
    if(isset($this->Security) && $this->RequestHandler->isAjax()){
        $this->Security->enabled = false;
        Configure::write('debug', 0);
        $this->autoRender=false;
        }   
}

function getname(){
 if (!empty($this->data)){
    //var_dump($this->data);

    $merryparent_info=$this->MerryParent->getMerryParents($this->data['MerryParent']['email']);
    //print_r($merryparent_info);
    $name=$merryparent_info['MerryParent']['name'];
    $this->set('name',$name);
    //$this->render('/merry_parents/ajax_input');
    }
}
function view(){
    //$name='';
    //var_dump($this->data);
    //$this->getname();
}

merry_parent.php模型

function getMerryParents($field_value){
    if (is_int($field_value))
        $conditions=array('merryParent.id'=>$field_value);
    else
        $conditions=array('merryParent.email'=>$field_value);

    //debug($conditions);

    $merryparent_info=$this->find('first',array(
                                'conditions'=>$conditions,
                                'recursive'=>-1   //fetches merry_parents table data only not the associated data
                                ));

    //debug($merryparent_info);
    return $merryparent_info;
}

Answer 1

尝试：


//add
$this->layout = false;  
//and instead of setting name simply echo the name from your function, like
echo $name;

希望有所帮助

jquery Ajax cakephp：电子邮件没有从数据库中获取和显示相应的名称

1 个答案: