Question

我正在尝试将数据发布到PHP Web服务我很熟悉使用查询$ .post在html中这样做，但我很难在目标C中尝试这个。我试过几个博客＆amp;在stackoverflow上找到的问题。

我终于想出了以下代码：

NSString *jsonRequest = [NSString stringWithFormat:@"{\"Email\":\"%@\",\"FirstName\":\"%@\"}",user,fname];
NSLog(@"Request: %@", jsonRequest);

NSURL *url = [NSURL URLWithString:@"http:myurl..."];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];
NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:[jsonRequest length]];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

NSURLConnection *connection = [NSURLConnection connectionWithRequest:request delegate:self];

我也尝试过：
NSURLConnection * connection = [[NSURLConnection alloc] initWithRequest：request delegate：self];

我的网络服务在帖子上创建新用户并返回用户ID。两者都成功进行Web服务调用（创建了新的用户ID），但是他们不发布数据，即每次都创建一个空白用户。
请告诉我我是否遗漏了什么。

感谢。

我的其他尝试：

NSMutableURLRequest *request = 
[[NSMutableURLRequest alloc] initWithURL:
 [NSURL URLWithString:@"myUrl.. "]];

[request setHTTPMethod:@"POST"];

NSString *postString = @"Email=me@test.com&FirstName=Test";

[request setValue:[NSString 
                   stringWithFormat:@"%d", [postString length]] 
forHTTPHeaderField:@"Content-length"];

[request setHTTPBody:[postString 
                      dataUsingEncoding:NSUTF8StringEncoding]];

[[NSURLConnection alloc] 
 initWithRequest:request delegate:self];

我终于解决了这个问题：最后，弄清楚出了什么问题。我使用http://mypath?params=123作为我的网址。我没有完整的网址（从不需要其他语言）。但在这里我需要给htt：//mypath/index.php？params = 123

Answer 1

我认为你最好像这样使用NSJSONSerialization类：

NSDictionary *tmp = [[NSDictionary alloc] initWithObjectsAndKeys:
                     email, @"Email",
                     fname, @"FirstName",
                     nil];
NSError *error;
NSData *postdata = [NSJSONSerialization dataWithJSONObject:tmp options:0 error:&error];
[request setHTTPBody:postData];

使用字典然后将其转换为JSON比创建字符串更容易。

祝你好运！

[ SWIFT 3.0 ]（更新）

let tmp = ["email": email,
           "FirstName": fname]
let postData = try? JSONSerialization.data(withJSONObject: tmp, options: .prettyPrinted)
request.httpBody = postData

Answer 2

我已运行您的代码，服务器端收到所有消息。

POST / HTTP/1.1
Host: linux-test
User-Agent: demoTest/1.0 CFNetwork/548.1.4 Darwin/11.3.0
Content-Length: 44
Accept: application/json
Content-Type: application/json
Accept-Language: en
Accept-Encoding: gzip, deflate
Connection: keep-alive

{"Email":"test@test.com","FirstName":"test"}

按照代码，如果jsonRequest包含非ASCII字符，则[jsonRequest length]将出错。

NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:[jsonRequest length]];

您可以改为使用strlen。

NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:strlen([jsonRequest UTF8String])];

或

[jsonRequest dataUsingEncoding:NSUTF8StringEncoding];

Answer 3

试试这个

NSData *requestData = [jsonRequest dataUsingEncoding:NSUTF8StringEncoding];

Answer 4

NSURL *url=[NSURL URLWithString:[NSString stringWithFormat:@"%@posts", SeverURL]];
ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
[request setRequestMethod:@"POST"];
[request addRequestHeader:@"content-type" value:@"application/json"];
[request addRequestHeader:@"User-Agent" value:@"iOS"];

request.allowCompressedResponse = NO;
request.useCookiePersistence = NO;
request.shouldCompressRequestBody = NO;
request.delegate=self;
NSString *json=[[self prepareData] JSONRepresentation];//SBJSON lib, convert a dict to json string
[request appendPostData:[NSMutableData dataWithData:[json dataUsingEncoding:NSUTF8StringEncoding]]];

[request startSynchronous];

使用Json在Objective C中发布数据

4 个答案: