Question

在我之前的问题Open a file from a specific program from python中，我发现了如何使用子进程来打开程序（Blender） - 以及特定的.blend文件 - 来自具有此代码的特定文件路径

import os
import subprocess

path = os.getcwd()
os.system("cd path/")
subprocess.check_call(["open", "-a", os.path.join(path, "blender.app"),"Import_mhx.blend"])

使用the help of a guy at a forum，我想在.blend文件中使用相对路径，因此我以这种方式更改了代码（对于Windows）

import os
import subprocess

# This should be the full path to your Blender executable.
blenderPath = "/cygdrive/c/Program Files/Blender Foundation/blender-2.62-release-windows32/blender.exe"

# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"

# This makes makes it so your script is currently based at "path1"
os.chdir(path1)

subprocess.check_call([blenderPath, "Import_mhx.blend"])

和Mac，

import os
import subprocess

path = os.getcwd()
os.system("cd path/")
print (path)
# This should be the full path to your Blender executable.
blenderPath = path + "/blender.app/Contents/macos/blender"

# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"

# This makes makes it so your script is currently based at "path1"
os.chdir(path1)

subprocess.check_call([blenderPath, "Import_mhx.blend"])

结果：

在Windows中，它运行正常。
在Mac上，结果是文件已打开，但程序似乎无法打开。我觉得很奇怪。

问题：

我是否应该为搅拌机（UNIX可执行文件）添加任何扩展名以便打开它？
我是否可以通过其他方式正确打开程序，还可以使用.blend文件中的相对路径？

Answer 1

import os
import subprocess

blenderPath = "./blender.app/Contents/MacOS/blender"

path1 = "./"

os.chdir(path1)

subprocess.check_call([ blenderPath, "Animation.blend"])

两个blender完全打开，并且.blend文件中的相对路径正常工作：）

从特定文件路径，相对路径，Unix可执行文件打开Blender（程序）

1 个答案: