Question

JPA / Hibernate缺少列

我使用JPA和Hibernate作为提供者。我有一个实体类，它有一个id列作为主键。这工作正常，但我现在必须修改它，因此主键是由两列组成的复合键。为了实现复合键，我使用了how to create a composite primary key hibernate JPA?

中显示的示例

以下是最后的课程：

主键

@Embeddable
public class DocumentPK implements Serializable {


    private static final long serialVersionUID = 1L;

    @Basic(optional = false)
    @Column(name="P_ID")
    private String pId;

    @Basic(optional = false)
    @Column(name="P_NAME")
    private String pName;

    public DocumentPK() {
    }

    public DocumentPK(String pId, int pName) {
        this.pId = pId;
        this.pName = pName;
    }

    public String getPId() {
        return pId;
    }

    public void setPId(String pId) {
        this.pId = pId;
    }

    public String getPName() {
        return pName;
    }

    public void setPName(String pName) {
        this.pName = pName;
    }

    @Override
    public int hashCode() {
        int hash = 0;
        hash += (pId != null ? pId.hashCode() : 0);
        hash += (int) pName;
        return hash;
    }

    @Override
    public boolean equals(Object object) {
        // TODO: Warning - this method won't work in the case the id fields are not set
        if (!(object instanceof DocumentPK)) {
            return false;
        }
        DocumentPK other = (DocumentPK) object;
        if ((this.pId == null && other.pId != null) || (this.pId != null && !this.pId.equals(other.pId))) {
            return false;
        }
        if (this.pName != other.pName) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return "[ pId=" + pId + ", pName=" + pName + " ]";
    }    
}

在实现上述主键之后，我更新了实体类以“嵌入”主键，如下所示。

@Entity
@Table(name="DOCUMENTS")

public class CustomerDocument implements Serializable{

    private static final long serialVersionUID = 6373600479711119252L;

    private     DocumentPK  id; 
    private     String  p_code;

    @EmbeddedId
    public DocumentPK getId() {
        return id;
    }

    public void setId(DocumentPK id) {
        this.id = id;
    }

    @Column(name="P_CODE")
    public String getPCode() {
        return p_code;
    }       
}

现在我检查了'DOCUMENTS'表，所有列都在那里。我甚至使用相同的用户登录到MySQL，我可以看到表格和相关列。如果我执行上述操作，则会抱怨没有找到P_ID列。我忘记了什么吗？

18:30:45,279 ERROR [TestContextManager] Caught exception while allowing TestExecutionListener [org.springframework.test.context.support.DependencyInjectionTestExecutionListener@1d349e2] to prepare test instance [com.bt.msm.ds.dao.BatchNumberDaoTest@97d3f0]
java.lang.IllegalStateException: Failed to load ApplicationContext
    at org.springframework.test.context.TestContext.getApplicationContext(TestContext.java:157)
    at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.injectDependencies(DependencyInjectionTestExecutionListener.java:109)
    at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.prepareTestInstance(DependencyInjectionTestExecutionListener.java:75)
    at org.springframework.test.context.TestContextManager.prepareTestInstance(TestContextManager.java:321)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.createTest(SpringJUnit4ClassRunner.java:211)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner$1.runReflectiveCall(SpringJUnit4ClassRunner.java:288)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.methodBlock(SpringJUnit4ClassRunner.java:290)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:231)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41)
    at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
    at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
    at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:174)
    at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
    at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor#0' defined in class path resource [my-spring-ds.xml]: Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [my-spring-jpa.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: myPersistenceUnit] Unable to build EntityManagerFactory
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456)
    at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:294)
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:225)
    at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:291)
    at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
    at org.springframework.context.support.AbstractApplicationContext.registerBeanPostProcessors(AbstractApplicationContext.java:728)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:449)
    at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:103)
    at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:1)
    at org.springframework.test.context.support.DelegatingSmartContextLoader.loadContext(DelegatingSmartContextLoader.java:228)
    at org.springframework.test.context.TestContext.loadApplicationContext(TestContext.java:124)
    at org.springframework.test.context.TestContext.getApplicationContext(TestContext.java:148)
    ... 24 more
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [msm-spring-jpa.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: myPersistenceUnit] Unable to build EntityManagerFactory
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1455)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456)
    at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:294)
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:225)
    at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:291)
    at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBeansOfType(DefaultListableBeanFactory.java:400)
    at org.springframework.beans.factory.BeanFactoryUtils.beansOfTypeIncludingAncestors(BeanFactoryUtils.java:275)
    at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.detectPersistenceExceptionTranslators(PersistenceExceptionTranslationInterceptor.java:139)
    at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.<init>(PersistenceExceptionTranslationInterceptor.java:79)
    at org.springframework.dao.annotation.PersistenceExceptionTranslationAdvisor.<init>(PersistenceExceptionTranslationAdvisor.java:70)
    at org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor.setBeanFactory(PersistenceExceptionTranslationPostProcessor.java:103)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeAwareMethods(AbstractAutowireCapableBeanFactory.java:1475)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1443)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519)
    ... 36 more
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: myPersistenceUnit] Unable to build EntityManagerFactory
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:892)
    at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:73)
    at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:257)
    at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:310)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1514)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452)
    ... 51 more
Caused by: org.hibernate.HibernateException: Missing column: pId in mydb.documents
    at org.hibernate.mapping.Table.validateColumns(Table.java:277)
    at org.hibernate.cfg.Configuration.validateSchema(Configuration.java:1174)
    at org.hibernate.tool.hbm2ddl.SchemaValidator.validate(SchemaValidator.java:139)
    at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:387)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1385)
    at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:954)
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:883)
    ... 56 more

Answer 1

我现在没有任何东西可以测试，但尝试将@EmbeddedId放在id-field而不是方法上。如果它不起作用，请尝试这样做：

DocumentPK：

public class DocumentPK implements Serializable {

    private static final long serialVersionUID = 1L;

    private String pId;

    private String pName;
    /* The rest of the class, notice the missing annotations */

CustomerDocument：

@Entity
@Table(name="DOCUMENTS")
@IdClass(DocumentPK.class)
public class CustomerDocument implements Serializable{

    private static final long serialVersionUID = 6373600479711119252L;

    @Id
    @Column(name="P_ID", nullable=false)
    private String pId;

    @Id
    @Column(name="P_NAME", nullable=false)
    private String pName;

    private     String  p_code;

    /* Getters and setters */

Answer 2

你的P_ID的getter和setter是错误的

   public String getpId() {
      return pId;
   }

   public void setpId(String pId) {
      this.pId = pId;
   }

应该是

public String getPId() {
    return pId;
}

public void setPId(String pId) {
    this.pId = pId;
}

希望有所帮助

<强>更新我使用了复合键以及我在代码中的配置方式，我的建议很少。

@Embeddable
public class DocumentPK implements Serializable {
    
    @Column(name="P_ID")
    private String pId;

    
    @Column(name="P_NAME")
    private String pName;

    //get set………
}


@Entity
@Table(name="DOCUMENTS")
public class CustomerDocument implements Serializable{

    private static final long serialVersionUID = 6373600479711119252L;

    @Id
    private     DocumentPK  id; 
    private     String  p_code;//hoping this is not typo better pCode

   //get set ……   
}

以类似的理由为我设置。

Answer 3

不久

将@Access（AccessType.FIELD）添加到DocumentPK类（如果您的实现支持JPA 2.0）或将注释从字段移动到方法（也适用于JPA 1.0实现）。

详细信息

正如您从日志中的错误消息中看到的那样：缺少列： pId ，所以它不是“没有找到 P_ID 列“。在DocumentPK中注释：

@Column(name="P_ID")

对您的情况没有影响，因为（来自JPA 2.0规范）：

可嵌入类的访问类型由访问权限决定实体类的类型，映射的超类或嵌入类嵌入它（包括作为元素集合的成员）独立于包含类的访问类型是否具有已明确指定或默认。一种不同的访问类型可以通过手段为该可嵌入类指定embeddable类如上所述的Access注释。

DocumentPK字段中的注释没有效果，因为它的访问类型是AccessType.PROPERTY。此访问类型派生自CustomerDocument。 CustomerDocument确实使用属性访问，因为找到的第一个映射注释是针对方法的（再次来自JPA 2.0规范）：

实体层次结构的默认访问类型由。确定将映射注释放置在实体的属性上没有的实体层次结构的类和映射的超类明确指定访问类型。

要使其工作，您必须使用@Access批注更改嵌入类中的访问类型，或将注释从字段移动到方法。

此外：您的代码无法编译，因为有时您将pName视为String，有时将其视为int。同样在“Java世界”中，通常的做法是使用camelCase名称而不是下划线作为单词分隔符。您还可以合并字段和方法的名称。

带有Hibernate的JPA - 如果实现复合键，则缺少列

3 个答案:

不久

详细信息