我想制作一个简单的动画。我的徽标分为4部分:
1 | 2
3 | 4
我想淡出每个部分,但只有一个接一个:1 - > 2 - > 4 - > 3 - > 1 ... 我对此没有任何问题,但有时我的动画不同步,4个部分同时动画:
final ImageView logo1 = (ImageView) v.findViewById(R.id.logo1);
logo1.clearAnimation();
final ImageView logo2 = (ImageView) v.findViewById(R.id.logo2);
logo2.clearAnimation();
final ImageView logo3 = (ImageView) v.findViewById(R.id.logo3);
logo3.clearAnimation();
final ImageView logo4 = (ImageView) v.findViewById(R.id.logo4);
logo4.clearAnimation();
final Animation anim1 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
anim1.setFillAfter(true);
anim1.setStartOffset(0);
final Animation anim2 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
anim2.setStartOffset(anim1.getDuration());
anim2.setFillAfter(true);
final Animation anim3 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
anim3.setStartOffset(anim1.getDuration()+anim2.getDuration());
anim3.setFillAfter(true);
final Animation anim4 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
anim4.setStartOffset(anim1.getDuration()+anim2.getDuration()+anim3.getDuration());
anim4.setFillAfter(true);
anim1.setAnimationListener(new AnimationListener() {
@Override
public void onAnimationStart(Animation animation) {}
@Override
public void onAnimationRepeat(Animation animation) {}
@Override
public void onAnimationEnd(Animation animation) {
anim1.setStartOffset(anim2.getDuration()+anim4.getDuration()+anim3.getDuration());
logo1.startAnimation(anim1);
}
});
anim2.setAnimationListener(new AnimationListener() {
@Override
public void onAnimationStart(Animation animation) {}
@Override
public void onAnimationRepeat(Animation animation) {}
@Override
public void onAnimationEnd(Animation animation) {
anim2.setStartOffset(anim1.getDuration()+anim4.getDuration()+anim3.getDuration());
logo2.startAnimation(anim2);
}
});
anim3.setAnimationListener(new AnimationListener() {
@Override
public void onAnimationStart(Animation animation) {}
@Override
public void onAnimationRepeat(Animation animation) {}
@Override
public void onAnimationEnd(Animation animation) {
anim3.setStartOffset(anim2.getDuration()+anim4.getDuration()+anim1.getDuration());
logo4.startAnimation(anim3);
}
});
anim4.setAnimationListener(new AnimationListener() {
@Override
public void onAnimationStart(Animation animation) {}
@Override
public void onAnimationRepeat(Animation animation) {}
@Override
public void onAnimationEnd(Animation animation) {
anim4.setStartOffset(anim2.getDuration()+anim1.getDuration()+anim3.getDuration());
logo3.startAnimation(anim4);
}
});
logo1.startAnimation(anim1);
logo2.startAnimation(anim2);
logo4.startAnimation(anim3);
logo3.startAnimation(anim4);
anim1.startNow();anim2.startNow();anim3.startNow();anim4.startNow();
有什么想法吗?
答案 0 :(得分:1)
仅启动anim1:
logo1.startAnimation(anim1);
并在anim1的AnimationListener的onAnimationEnd中执行:
logo2.startAnimation(anim2);
这样anim2将在anim1完成之前不会启动。