Question

用户选择一个选项，在这种情况下选项1 - Brew。然后他们输入URL，在本例中为BREW。我现在只检查BREW这个词，所以咖啡：// 127 ......在这个阶段是无关紧要的。

从服务器收到消息响应。注意在第一个服务器响应消息中发送了200 OK。

应用程序继续循环，用户再次进入URL，这也是BREW。

此次问题是返回400 Bad Request消息。由于URL是正确的，它们应该像应用程序的第一次传递一样接收200 OK。

客户端控制台：

WELCOME TO THE COFFEE POT APPLICATION!

Select an option:
1. Brew
2. Quit
1
Enter URL (e.g. BREW coffee://127.0.0.1/pot-1 HTCPCP-new )
BREW

MESSAGE FROM SERVER:
    Message: BREW Accept-Additions: *, *, *, *, *, *, *, 
    HTCPCP-new 200 OK BREW START command completed.
    Content-length:  44
    Content-type: application/octet-stream
    @@

Select an option:
1. Brew
2. Quit
1
Enter URL (e.g. BREW coffee://127.0.0.1/pot-1 HTCPCP-new )
BREW

MESSAGE FROM SERVER:
    Message: BREW Accept-Additions: *, *, *, *, *, *, *,  
    HTCPCP-new 400 Bad Request.
    Content-length:  5
    Content-type: application/octet-stream
    @@

Select an option:
1. Brew
2. Quit

客户端线程处理程序：

import java.io.*;
import java.net.*;
import javax.activation.MimetypesFileTypeMap;

public class HTCPCPClientWorker extends Thread {

    Socket cwsocket = null;

    public HTCPCPClientWorker(Socket cwsocket) {
        super("ClientWorker");
        this.cwsocket = cwsocket;
    }

    @Override
    public void run() {

        String clientSentence = null;
        BufferedReader inFromClient = null;
        PrintWriter outToClient = null;

        try {
            inFromClient = new BufferedReader(new InputStreamReader(cwsocket.getInputStream()));
            outToClient = new PrintWriter(cwsocket.getOutputStream(), true);
        } catch (IOException ex) {
            System.err.println("Cannot create streams");
        }

        try {

            do { // end when client says QUIT

                StringBuffer clientInputLine[] = new StringBuffer[3];

                clientInputLine[0] = new StringBuffer();
                clientInputLine[1] = new StringBuffer();

                // Get next message from client 
                for (int i = 0; i <= clientInputLine.length; i++) {

                    // read input line from BufferedReader 
                    clientSentence = inFromClient.readLine();

                    if (clientSentence.contains("BREW")) {
                        outToClient.println("Message: " + clientSentence);
                        outToClient.println("HTCPCP-new 200 OK BREW START command completed.");
                        outToClient.println("Content-length:  " + clientSentence.length()); // length needs to correspond to above line 
                        outToClient.println("Content-type: " + new MimetypesFileTypeMap().getContentType(clientSentence));
                        outToClient.println("@@");
                        outToClient.flush();
                    } else {
                        outToClient.println("Message: " + clientSentence);
                        outToClient.println("HTCPCP-new 400 Bad Request.");
                        outToClient.println("Content-length:  " + clientSentence.length()); // length needs to correspond to above line 
                        outToClient.println("Content-type: " + new MimetypesFileTypeMap().getContentType(clientSentence));
                        outToClient.println("@@");
                        outToClient.flush();
                    }

                    // wait for EOF = @@ 
                    System.out.println("\tInput: " + clientSentence);
                    if (clientSentence.equals("@@") == true) {
                        break;
                    }
                    clientInputLine[i].append(clientSentence);
                } // end for loop


            } while (!clientSentence.contains("QUIT"));

            outToClient.println("GOODBYE!");
            outToClient.flush();

            System.out.println("\tClient has disconnected.");
            cwsocket.close();

        } catch (IOException e) {
            e.printStackTrace();
        }
    } // end run

} // end HTCPCPClientWorker.java

我认为通过在每次传递中重新创建StringBuffer可以解决问题，但事实并非如此。

第3遍及以后似乎正常运作。

有什么想法？

Answer 1

我相信每次要从套接字读取时都应该重新创建BufferedReader（inFromClient）。使用readLine后，BufferedReader变空，因此下次将输入放在套接字上时，他不会读取它。

有关读取和写入套接字here的更多信息。

Java中第二遍传递的不规则输出

1 个答案: