c ++部门。看似简单的事让我抓狂,请指教

时间:2012-03-19 07:06:31

标签: c++

好的,我已经编程了大约一个星期,我开始使用c ++。我正在编写一个程序,这是一种算术训练器,你输入你想要的方程式数量,你输入随机数发生器的极限,你指定你想要的方程式(/ * - +) ,然后程序使用for循环并通过并在var中生成方程式及其答案,然后针对此var检查用户输入,如果它们匹配另一个正在计数的正确答案的var,则递增。在最后一个等式之后,程序告诉用户他们从多少个等式得到了多少,并且通过将正确答案的数量除以问题量,然后将该值乘以100 u应该获得该用户算术会话的准确度百分比。问题是c ++不断向我返回一个friggin 0值,我不能为我的生活解决为什么在世界上c ++正在这样做。

整个计划:

#include <iostream>
#include <string>
#include <ctime>
#include <cstdlib>
using namespace std;
void menu(void);
class session{
public:
session(){
            create_session();
        }
        void create_session(void){
        amount = 0;
        range_limit = 0;
        rights = 0;
        answer = 0;
        input = 0;
        type = "";
        while(amount == 0){
            cout << "\nHow many equations do you want?: "; cin >> amount;
            if(amount < 1){
                cout << "\nAmount is too low!";
                amount = 0;
            }
        }
        while(range_limit == 0){
            cout << "Enter the number range limit: "; cin >> range_limit;
            if(range_limit < 1){
                cout << "\nRange limit too low!";
                range_limit = 0;
            }
        }
        while(type == ""){
            cout << "What equation type do you want?: "; cin >> type;
            int strlen = type.size();
            if(strlen < 1){
                cout << "Invalid type input!";
                type = "";
            }
        }
        if(type == "+"){
            for(int i=0;i<amount;i++){
                int a = random();
                int b = random();
                answer = a + b;
                cout << "\n" << a << " + " << b << " = "; cin >> input;
                if(answer == input){
                    rights++;
                }
            }
        }
cout << "\nYou got " << rights << " answers right out of " << amount <<         " equations." << endl;
        cout << "Accuracy percentage: " << getAccuracy() << "%" << endl;
        int post_menu=0;
        while(post_menu == 0){
            cout << "Enter 1 to create another session or 2 to return to the menu: ";
            cin >> post_menu;
            if(post_menu == 1){
                create_session();
            }else if(post_menu == 2){
                menu();
            }else{
                cout << "Invalid input: ";
                post_menu = 0;
            }
        }
    }
    float getAccuracy(){
           float x = (rights/amount)*100;
           return x;
    }
    int random(){
        int x = 1+(rand()%range_limit);
        return x;
    }
    void set_amount(int a){
        amount = a;
    }
    void set_range_limit(int r){
        range_limit = r;
    }
    void set_rights(int R){
        rights = R;
    }
    void set_answer(int a){
        answer = a;
    }
    void set_input(int i){
        input = i;
    }
    void set_type(string t){
        type = t;
    }
private:
    int amount;
    int accuracy;
    int range_limit;
    int rights;
    int answer;
    int input;
    string type;

};
int main(){
cout << "=== WELCOME TO ARITH! === \n=========================\n";
menu();
return 0;
}

void menu(void){
//Set the seed for random number gen.
srand(time(0));

 //Set var for getting menu input, then get the menu input..
 int menu_input;
 cout << "\n[1]Create a Session. [2]Exit Arith. \nWhat would you like to do?: ";
 cin >> menu_input;

 //Now we check what the user wants and act accordingly..
 if(menu_input > 2){
    cout << "error";
    menu_input=0;
 }else if(menu_input == 1){
     session start;
 }else if(menu_input == 2){
    cout << "\nExiting Arith!";
 }else{
    cout << "error";
    menu_input=0;
 }
}

麻烦的部分:

    float getAccuracy(){
           float x = (rights/amount)*100;
           return x;

一些程序如何返回0%。

任何人都知道为什么会这样,以及如何获得结果。

2 个答案:

答案 0 :(得分:4)

rightsamount都是int,因此当您划分时,该值会被覆盖,例如,如果您执行5/2,则答案为2而不是2.5。要解决此问题,您需要将变量之一投射到float,如下所示:(float(rights)/amount) * 100

答案 1 :(得分:1)

当两个int数被分割时,即使临时变量,结果也将是int。所以你可以使任何变量浮动或加倍或投射它。

您只需要转换一种数据类型,因为另一种数据类型将是隐式类型提升。

float x = ((double)rights/amount)*100;

或者如果它不影响代码的任何其他部分,你可以默认使你的数量变量浮动。

你也可以选择静态演员:

float x = (static_cast<double>(rights)/amount)*100;