您好我在将数据从php发送到pdf时遇到了问题。我认为唯一的方法是将一个变量放入将发送到pdf函数的数据中。 这是我需要放入php变量的代码..
<table width="95%" height="95%">
<tr>
<td align="center">
<table width="100%" border="0" cellpadding="2" cellspacing="2">
<tr align="center">
<td colspan="7" bgcolor="#2561cf" style="color:#FFFFFF"><strong><?php echo $monthNames[$cMonth-1].' '.$cYear; ?></strong></td>
</tr>
<tr>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Sun</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Mon</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Tue</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Wed</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Thu</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Fri</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Sat</strong></td>
</tr>
<?php
$timestamp = mktime(0,0,0,$cMonth,1,$cYear);
$maxday = date("t",$timestamp);
$thismonth = getdate ($timestamp);
$startday = $thismonth['wday'];
for ($i=0; $i<($maxday+$startday); $i++) {
$day = ($i - $startday + 1);
if($day['1'] == '1' || $day['1'] == '2' || $day['1'] == '3' || $day['1'] == '4' || $day['1'] == '5' || $day['1'] == '6' || $day['1'] == '7' || $day['1'] == '8' || $day['1'] == '9'){
$day = '0'.$day;
}else{
$day = $day;
}
$date = $monthNames[$cMonth-1].' '.$day.', '.$cYear;
$date2 = $cMonth.'/'.$day.'/'.$cYear;
$events = $this->getEvents($date2);
if(($i % 7) == 0 ) echo "<tr>\n";
if($i < $startday) echo "<td></td>\n";
else echo "<td valign='top' align='left' width='50px' height='50px'><div class='".$dateId."' id='".$date."' title='".$date2."' style='cursor:pointer;'>". ($i - $startday + 1) .'</div>'. $events."</td>\n";
if(($i % 7) == 6 ) echo "</tr>\n";
}
?>
</table>
</td>
</tr>
</table>
答案 0 :(得分:4)
如果您有大量的HTML / PHP,并且需要将输出存储在变量中而不是打印到屏幕上,则可以使用output buffering函数来简化:
<?php
ob_start(); // Start the buffer (nothing will be output)
?>
<p>Lots and lots of mixed <?php echo 'HTML'; ?> and PHP...</p>
<?php
$content = ob_get_clean(); // End the buffer and assign everything to $content
?>
答案 1 :(得分:1)
可以尝试连接将代码放在函数中的循环。 实施例
function test(){
echo '{the code}';
}
$var = test();
答案 2 :(得分:0)
虽然我不完全明白你的要求,但我会尝试回答它!
如果你想要在变量中使用PHP而不是使用echo来显示当前显示在页面上的所有内容,那么你将希望将该信息附加到变量上,所以...
<?php
$timestamp = mktime(0,0,0,$cMonth,1,$cYear);
$maxday = date("t",$timestamp);
$thismonth = getdate ($timestamp);
$startday = $thismonth['wday'];
for ($i=0; $i<($maxday+$startday); $i++) {
$day = ($i - $startday + 1);
if($day['1'] == '1' || $day['1'] == '2' || $day['1'] == '3' || $day['1'] == '4' || $day['1'] == '5' || $day['1'] == '6' || $day['1'] == '7' || $day['1'] == '8' || $day['1'] == '9'){
$day = '0'.$day;
}else{
$day = $day;
}
$date = $monthNames[$cMonth-1].' '.$day.', '.$cYear;
$date2 = $cMonth.'/'.$day.'/'.$cYear;
$events = $this->getEvents($date2);
if(($i % 7) == 0 ) echo "<tr>\n";
if($i < $startday) echo "<td></td>\n";
else echo "<td valign='top' align='left' width='50px' height='50px'><div class='".$dateId."' id='".$date."' title='".$date2."' style='cursor:pointer;'>". ($i - $startday + 1) .'</div>'. $events."</td>\n";
if(($i % 7) == 6 ) echo "</tr>\n";
}
?>
会变成......
<?php
$send_me_to_pdf = '';
$timestamp = mktime(0,0,0,$cMonth,1,$cYear);
$maxday = date("t",$timestamp);
$thismonth = getdate ($timestamp);
$startday = $thismonth['wday'];
for ($i=0; $i<($maxday+$startday); $i++) {
$day = ($i - $startday + 1);
if($day['1'] == '1' || $day['1'] == '2' || $day['1'] == '3' || $day['1'] == '4' || $day['1'] == '5' || $day['1'] == '6' || $day['1'] == '7' || $day['1'] == '8' || $day['1'] == '9'){
$day = '0'.$day;
}else{
$day = $day;
}
$date = $monthNames[$cMonth-1].' '.$day.', '.$cYear;
$date2 = $cMonth.'/'.$day.'/'.$cYear;
$events = $this->getEvents($date2);
if(($i % 7) == 0 ) $send_me_to_pdf .= "<tr>\n";
if($i < $startday) $send_me_to_pdf .= "<td></td>\n";
else $send_me_to_pdf .= "<td valign='top' align='left' width='50px' height='50px'><div class='".$dateId."' id='".$date."' title='".$date2."' style='cursor:pointer;'>". ($i - $startday + 1) .'</div>'. $events."</td>\n";
if(($i % 7) == 6 ) $send_me_to_pdf .= "</tr>\n";
}
?>
现在,您可以使用$ send_me_to_pdf作为要发送此数据的PDF函数的参数吗?
答案 3 :(得分:0)
尝试联合变量
<?php
$var='
<table width="95%" height="95%">
<tr>
<td align="center">
<table width="100%" border="0" cellpadding="2" cellspacing="2">
<tr align="center">
<td colspan="7" bgcolor="#2561cf" style="color:#FFFFFF"><strong>'.$monthNames[$cMonth-1].' '.$cYear.'</strong></td>
</tr>
<tr>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Sun</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Mon</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Tue</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Wed</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Thu</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Fri</strong></td>
<td align="center" bgcolor="#2561cf" style="color:#FFFFFF"><strong>Sat</strong></td>
</tr>';
?>
<?php
$timestamp = mktime(0,0,0,$cMonth,1,$cYear);
$maxday = date("t",$timestamp);
$thismonth = getdate ($timestamp);
$startday = $thismonth['wday'];
for ($i=0; $i<($maxday+$startday); $i++) {
$day = ($i - $startday + 1);
if($day['1'] == '1' || $day['1'] == '2' || $day['1'] == '3' || $day['1'] == '4' || $day['1'] == '5' || $day['1'] == '6' || $day['1'] == '7' || $day['1'] == '8' || $day['1'] == '9'){
$day = '0'.$day;
}else{
$day = $day;
}
$date = $monthNames[$cMonth-1].' '.$day.', '.$cYear;
$date2 = $cMonth.'/'.$day.'/'.$cYear;
$events = $this->getEvents($date2);
if(($i % 7) == 0 ) echo "<tr>\n";
if($i < $startday) echo "<td></td>\n";
$var.= "<td valign='top' align='left' width='50px' height='50px'><div class='".$dateId."' id='".$date."' title='".$date2."' style='cursor:pointer;'>". ($i - $startday + 1) .'</div>'. $events."</td>\n";
if(($i % 7) == 6 )
$var.="</tr>\n";
}
$var.=' </table>
</td>
</tr>
</table>';
?>
最终结果位于 $ var