Question

我正在尝试将下面的较长代码转换为较短的代码，我的代码是针对Actionscript 2，而我使用as2调试器，trace（），它获取循环，但它不会识别是一个movieclip（button1 - button3是我指定的3个不同的电影剪辑）。

来自这个

button1.onRollOver = function(){
m_bt1.scaleTo(70, 1, "easeoutelastic");
};

button1.onRollOut = function(){
m_bt1.scaleTo(100, 1, "easeoutelastic");
};

button2.onRollOver = function(){
m_bt2.scaleTo(70, 1, "easeoutelastic");
};

button2.onRollOut = function(){
m_bt2.scaleTo(100, 1, "easeoutelastic");
};

button3.onRollOver = function(){
    m_bt3.scaleTo(70, 1, "easeoutelastic");
};

button3.onRollOut = function(){
    m_bt3.scaleTo(100, 1, "easeoutelastic");
};

到此：

var $i;
for($i=1; $i <4; $i++){
    var main_bt = 'button'+$i;
    _root.main_bt.onRollOut = function(){
        this.main_bt.scaleTo(70, 1, "easeoutelastic");
    }
}

Answer 1

首先尝试将按钮放在数组中，然后迭代数组：

var buttons = [button1, button2, button3];
for(var index=0; index < buttons.length; index++){ 
    var main_bt = buttons[index]; 
    main_bt.onRollOut = function(){ 
        this.main_bt.scaleTo(70, 1, "easeoutelastic"); 
    } 
}

或者也可以继续工作：var button = _root['button'+$i]

将长代码转换为更短的循环ActionScript 2

1 个答案: