Question

当我调试代码包含SocketChannel在Android中编写时，我得到了IllegalArgumentException，但是在Windows中相同的代码没有这个例外，在SocketChannel写的Android和windows之间有区别吗？

更新：（该代码是开源项目frostwire-android（this file in github）的一部分，这部分与vuze 4.5相同，我只是添加一个try {}）

private int channelWrite(ByteBuffer buf) throws IOException
{
    int written = 0;
    while(remainingBytesToScatter > 0 && buf.remaining() > 0)
    {
        int currentWritten = 0;
        try{
            currentWritten = channel.write((ByteBuffer)(buf.slice().limit(Math.min(50+rnd.nextInt(100),buf.remaining()))));
        }catch( Exception e ) {
            if(e instanceof IOException) {
                Log.d("", "chanel write IOException " + e.getMessage());
            }else if(e instanceof IOException) {
                Log.d("", "chanel write AsynchronousCloseException " + e.getMessage());
            }else if(e instanceof ClosedByInterruptException) {
                Log.d("", "chanel write ClosedByInterruptException " + e.getMessage());
            }else if(e instanceof ClosedChannelException) {
                Log.d("", "chanel write ClosedChannelException " + e.getMessage());
            }else if(e instanceof NotYetConnectedException) {
                Log.d("", "chanel write ClosedChannelException " + e.getMessage());
            }else {
                // while in second time, reach here
                Log.d("", "chanel write unknown " + e.getMessage());
            }
        }

        if(currentWritten == 0)
            break;
        buf.position(buf.position()+currentWritten);
        remainingBytesToScatter -= currentWritten;
        if(remainingBytesToScatter <= 0)
        {
            remainingBytesToScatter = 0;
            try
            {
                channel.socket().setTcpNoDelay(false);
            } catch (SocketException e)
            {
                Debug.printStackTrace(e);
            }
        }
        written += currentWritten;
    }

    if(buf.remaining() > 0)
        written += channel.write(buf);

    return written;     
}

Answer 1

行为由同一个合同（标准库文档）定义，并且该文档没有为任何特定于实现的解释提供空间，因此您的问题的答案必须是，不，行为之间应该没有区别Android和Windows上的行为。

顺便说一句，the documentation并未说该方法可能会抛出IllegalArgumentException。你确定从该方法抛出了异常吗？我建议你为此提供一个SSCCE。

Java中的Java SocketChannel编写（ByteBuffer源码）与Windows不同吗？

1 个答案: