大家好,我在这里有点堆叠。当我运行程序并按下提交按钮时,它应该每2秒更换4张图片。但是它不会重新显示图像。如果有人能帮我一把,那就太好了。我正在使用eclipse,程序正在编译和运行。这是代码。
/** Here is the GUI of the program
* class name SlideShowGui.java
* @author Kiril Anastasov
* @date 07/03/2012
*/
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;
public class SlideShowGui extends JPanel implements ActionListener, Runnable
{
JLabel name, comments, images;
JTextField namejtf, commentsjtf, captionjtf;
JButton submit;
ImageIcon pictures1, pictures2, pictures3, pictures4;
//ImageIcon []pictures2 = {galileo1.jpg};
SlideShowGui()
{
name = new JLabel("Name:");
this.add(name);
namejtf = new JTextField(15);
this.add(namejtf);
comments = new JLabel("Comments:");
this.add(comments);
commentsjtf = new JTextField(15);
this.add(commentsjtf);
submit = new JButton("Submit");
this.add(submit);
submit.addActionListener(this);
pictures1 = new ImageIcon("galileo1.jpg");
images = new JLabel(pictures1);
this.add(images);
pictures2 = new ImageIcon("galileo2.jpg");
this.add(images);
pictures3 = new ImageIcon("galileo3.jpg");
this.add(images);
pictures4 = new ImageIcon("galileo4.jpg");
this.add(images);
captionjtf = new JTextField(24);
this.add(captionjtf);
//pictures = new ImageIcon("galileo1.jpg");
// images.setIcon(pictures);
}
public void actionPerformed(ActionEvent ae)
{
Thread t = new Thread(this);
t.start();
if(ae.getSource() == submit)
{
int i = 0;
boolean go = true;
while(go)
{
i++;
System.out.println(i);
try
{
Thread.sleep(2000);
if(i == 1)
{
pictures1 = new ImageIcon("galileo1.jpg");
images.setIcon(pictures1);
System.out.println("picture 1 should be displayed here");
}
if(i == 2)
{
pictures2 = new ImageIcon("galileo2.jpg");
images.setIcon(pictures2);
System.out.println("picture 2 should be displayed here");
}
if(i == 3)
{
pictures3 = new ImageIcon("galileo3.jpg");
images.setIcon(pictures3);
System.out.println("picture 3 should be displayed here");
}
if(i == 4)
{
pictures4 = new ImageIcon("galileo4.jpg");
images.setIcon(pictures4);
System.out.println("picture 4 should be displayed here");
}
if(i == 4)
{
i = 0;
}
}
catch (InterruptedException ie)
{
System.out.println("thread exception");
}
}
}
}
public void run()
{
}
}
/**The driver class of the program. Here is the JFrame
* class name TestSlideShow.java
* @author Kiril Anastasov
* @date 07/03/2012
*/
import java.awt.*;
import javax.swing.*;
public class TestSlideShow
{
public static void main(String[] args)
{
JFrame application = new JFrame();
SlideShowGui panel = new SlideShowGui();
application.add(panel);
application.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
application.setSize(300,600);
application.setLocation(400,100);
application.setVisible(true);
}
}
答案 0 :(得分:5)
始终使用javax.swing.Timer
至少在Swing中使用Thread.sleep(...)
。在此尝试此代码,但请将path
替换为您的图片:
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class SlideShow extends JPanel
{
private int i = 0;
private Timer timer;
private JLabel images = new JLabel();
private Icon bg = UIManager.getIcon("OptionPane.warningIcon");
private Icon red = UIManager.getIcon("OptionPane.errorIcon");
private Icon blue = UIManager.getIcon("OptionPane.informationIcon");
private ImageIcon pictures1, pictures2, pictures3, pictures4;
private ActionListener action = new ActionListener()
{
public void actionPerformed(ActionEvent ae)
{
boolean go = true;
i++;
System.out.println(i);
if(i == 1)
{
images.setIcon(bg);
System.out.println("picture 1 should be displayed here");
}
if(i == 2)
{
images.setIcon(red);
System.out.println("picture 2 should be displayed here");
}
if(i == 3)
{
images.setIcon(blue);
System.out.println("picture 3 should be displayed here");
}
if(i == 4)
{
images.setIcon(bg);
System.out.println("picture 4 should be displayed here");
}
if(i == 5)
{
go = false;
timer.stop();
System.exit(0);
}
revalidate();
repaint();
}
};
public SlideShow()
{
JFrame frame = new JFrame("SLIDE SHOW");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLocationByPlatform(true);
frame.getContentPane().add(this);
add(images);
frame.setSize(300, 300);
frame.setVisible(true);
timer = new Timer(2000, action);
timer.start();
}
public static void main(String... args)
{
SwingUtilities.invokeLater(new Runnable()
{
public void run()
{
new SlideShow();
}
});
}
}
答案 1 :(得分:4)
整个if (i == ...
部分可以简化。在SlideShowGUI
中声明一个静态类成员:
private final static ImageIcon[] icons = {new ImageIcon("galileo1.jpg"),
new ImageIcon("galileo2.jpg"),
new ImageIcon("galileo3.jpg"),
new ImageIcon("galileo4.jpg")};
并将其用于替换if
语句:
images.setIcon(icons[i-1]);
System.printf("Picture %s should be displayed%n", i-1);
if (i == 4) {
i = 0;
}
答案 2 :(得分:4)
您可以像Andreas_D提到的那样简化代码。
当您调用Thread.sleep()
时,您当前的设计将阻止主线程,这会冻结您的应用程序。
如果您想更新Image
,则应在run()
方法中实施更新代码。
因此,如果您检测到用户按下提交JButton
,请创建并启动新的Thread
以更新用户界面。