Question

我有一个文本文件格式的日志文件。日志文件看起来像以下格式

220.227.40.118 - - [06/Mar/2012:00:00:00 -0800] "GET /mysidebars/newtab.html 
HTTP/1.1" 404 0 - -
220.227.40.118 - - [06/Mar/2012:00:00:00 -0800] "GET /hrefadd.xml HTTP/1.1" 
204 214 - -
59.95.13.217 - - [06/Mar/2012:00:00:00 -0800] "GET /dbupdates2.xml HTTP/1.1" 
404 0 - -

111.92.9.222 - - [06/Mar/2012:00:00:00 -0800] "GET /mysidebars/newtab.html 
HTTP/1.1" 404 0 - -
120.56.236.46 - - [06/Mar/2012:00:00:00 -0800] "GET /hrefadd.xml HTTP/1.1" 
204 214 - -
49.138.106.21 - - [06/Mar/2012:00:00:00 -0800] "GET /add.txt HTTP/1.1" 204 
214 - -

117.195.185.130 - - [06/Mar/2012:00:00:00 -0800] "GET 
/mysidebars/newtab.html HTTP/1.1" 404 0 - -
122.160.166.220 - - [06/Mar/2012:00:00:00 -0800] "GET 
/mysidebars/newtab.html HTTP/1.1" 404 0 - -
117.214.20.28 - - [06/Mar/2012:00:00:00 -0800] "GET /welcome.html HTTP/1.1" 
204 212 - -
117.18.231.5 - - [06/Mar/2012:00:00:00 -0800] "GET /mysidebars/newtab.html 
HTTP/1.1" 404 0 - -

我想使用python找到日志文件中的每个唯一IP地址。

Answer 1

怎么样：

def get_ips(logfile):
    with open(logfile, 'r') as f:
        for line in f.readlines():
            yield line.split()[0]


def main():
    for ip in set(get_ips('log.txt')):
        print ip


if __name__ == '__main__':
    main()

Answer 2

以下是：

def unique_ips():
    f = open('log_file.txt','r')
    ips = set()
    for line in f:
        ip = line.split()[0]
        ips.add(ip)
    return ips

if __name__=='__main__':
    print unique_ips()

这适用于python 2.6。

如何使用python从日志文件中的ip地址列表中获取唯一的ip地址？

2 个答案: