Question

我在编写一个简单的循环任务时遇到了麻烦。我需要循环来做的事情如下：

1）提示用户询问什么是50 + 10 =

2）如果用户输入了错误的答案，则会弹出一条警告消息，说明他们还有2次尝试

3）一旦用户耗尽他们所有的尝试，就会弹出一条不同的消息，说明你没有再尝试

这是我能够提出的：

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int attempt = 1;
int answer = 60;

for( attempt = 1; attempt < 0; --attempt)

System.out.print(" 50 + 10 = ");
answer = input.nextInt();
input.nextLine();

    if( answer != 60)
    {
        System.out.printf( "Invalid! Try Again! %d attempt(s) left! ", attempt);

        System.out.print( "\n50 + 10 = " );
        answer = input.nextInt();
    }

        if( attempt == 0)
        {
            System.out.print( "Sorry!  You have no more attempts left!" );
        }

System.exit(0);
}

如果我将控制变量的值从1改为2，则打印50 + 10 = 50 + 10 =

当我运行该程序时，它将输出0次尝试而不是2次尝试，然后是1，然后是抱歉消息。

Answer 1

看看这里......我已经在某种程度上对其进行了修改......

for( attempt = 1; attempt >= 0; --attempt)
        {
        System.out.print(" 50 + 10 = ");
        answer = input.nextInt();
        input.nextLine();

            if( answer != 60)
            {

                if(attempt!=0)
                    {
                     System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
                        continue;
                    }
                else
                     System.out.print( "Sorry!  You have no more attempts left!" );

            }
                System.exit(0);
    }

用于循环输出

1 个答案: