说我有一张表如下
Employee RecNumber
Joe Bloggs 123456
Joe Bloggs 123456
Bob Bloggs 123457
Dup Bloggs 123456
我只想返回所有Rec Number,其中2人拥有相同的RecNumber,这不应该发生。 请注意,一个人可以多次拥有相同的请求编号,我只想要返回,其中2个人具有相同的编号
所以我想要的就是
123456
答案 0 :(得分:2)
select record_number
from my_table
group by record_number
having count(distinct employee) > 1
答案 1 :(得分:0)
SELECT A.RECNUMBER,COUNT(B.EMPLOYEE)
(SELECT DISTINCT RECNUMBER FROM YOURTABLE) A,
YOURTABLE B
WHERE A.RECNUMBER = B.RECNUMBER
GROUP BY A.RECNUMBER
HAVING COUNT(B.EMPLOYEE)=2;
答案 2 :(得分:0)
这样的东西?
SELECT RecNumber FROM Table GROUP BY RecNumber HAVING COUNT(*) > 1
答案 3 :(得分:0)
SELECT RecNumber FROM [a table]
GROUP BY RecNumber HAVING COUNT(*) > 1;
或者
SELECT RecNumber FROM (SELECT RecNumber, Employee
FROM [a table]
GROUP BY RecNumber, Employee HAVING COUNT(*) > 1
) AS x;
答案 4 :(得分:0)
你可以写类似的东西,我认为它有效:
use *DATABASE_NAME*
go
select *Your_Field*, Nbre=count(*Your_Field*) from *TABLE_NAME*
group by *Your_Field*
having count(*Your_Field*)>1
order by 2 desc
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