Question

如何在我的c＃WEBMETHOD..so中将一个json对象的字符串转换为动态，以便我可以使用它来检索数据。

示例我的ajax电话

 function do_save_data()
    {
      $.ajax({
         type:"POST",
         url:"../mymethods/test.aspx/SaveUser",
         data:"{'profile':'"+objrecieved+"'}",
         contentType:"application/json; charset=utf-8",
         success:function(msg){}
      });

} 



[WebMethod]
public void save data(object profile)
{
    JavaScriptSerializer _myserliaser=new JavaScriptSerializer();
    dynamic data=(dynamic)_myserliaser.DeseralizeObject(profile);

    //problem here is it is taking it as a string.hence when it try
    string name=data.name.ToString();
    //error 'string' does not contain a definition for 'name'



}

任何人都可以告诉我如何处理来自ajax调用的对象作为字符串并将其置于动态并获取其详细信息提前致谢

Answer 1

JavaScriptSerializer将JSON字符串封装为Dictionary，您不能将其强制转换为动态，否则您将失去属性，最好的办法是将字典转换为可轻松转换为动态的ExpandoObject。这是一个扩展方法：

public static class JavaScriptSerializerExtension
{
    public static dynamic DeserializeDynamic(this JavaScriptSerializer serializer, string value)
    {
        var dic = serializer.Deserialize<IDictionary<string, object>>(value);
        return ToExpando(dic);
    }

    private static ExpandoObject ToExpando(IDictionary<string, object> dic)
    {
        var expando = new ExpandoObject() as IDictionary<string, object>;

        foreach (var item in dic)
        {
            var prop = item.Value as IDictionary<string, object>;
            expando.Add(item.Key, prop == null ? item.Value : ToExpando(prop));
        }

        return (ExpandoObject)expando;
    }
}

您可以使用JavaScriptSerializer对象的DeserializeDynamic扩展方法反序列化为动态

如何将从jquery接收的字符串转换为c＃动态对象？

1 个答案: