Question

我在Android学习webservices，我做了一个简单的应用程序，我发送一个文本从android到mysql。我已为此编写代码。工作正常，但必须存储在表中的值重复4次。想不明白为什么？拜托我需要你的帮忙。这是我的代码。 MYSQL只包含两列CITY_ID和CITY_NAME

public class Insert extends Activity {
    String[] ct_name = null;

    Button button;
    InputStream is = null;
    EditText name;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
         setContentView(R.layout.main);

        name = (EditText) findViewById(R.id.textname);

        button = (Button) findViewById(R.id.textbutton);

        button.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                String textn = name.getText().toString();
                ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();       
                nameValuePairs.add(new BasicNameValuePair("c_name",textn));
                try{
                    HttpClient httpclient = new DefaultHttpClient();
                    HttpPost httppost = new HttpPost("http://10.0.2.2/city1.php");
                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                    HttpResponse response = httpclient.execute(httppost);
                    HttpEntity entity = response.getEntity();
                    is = entity.getContent();
                    }catch(Exception e){
                    Log.e("log_tag", "Error in http connection"+e.toString());
                    }


            }
        });
        // http post

        }

    }

php代码如下

<?php

$hostname_localhost ="localhost";
$database_localhost ="mydatabase";
$username_localhost ="root";
$password_localhost ="";

$localhost = mysql_connect($hostname_localhost,$username_localhost,$password_localhost)
or
trigger_error(mysql_error(),E_USER_ERROR);

mysql_select_db($database_localhost);
$query="INSERT INTO CITY (`CITY_NAME`)VALUES('".$_POST['c_name']."')";
$exec=mysql_query($query);
if(!$exec)
echo "Error in query: ".mysql_error();
mysql_close();
?>

这是ddms

中显示的错误

http connectionorg.apache.http.NoHttpResponseException中的错误：目标服务器无法响应

在MySql：Simple Http Post中从android重复发送数据

0 个答案: