Question

这是我的输入xml，希望消除<SRNumber>1</SRNumber>但合并childServiceRequest_LXKCTrackCodes。感谢任何帮助，在这一天打破我的头脑输入XML：

<ServiceRequest> <SRNumber>1</SRNumber> 
<ServiceRequest_LXKCTrackCodes> 
<Note>Test1</Note> 
</ServiceRequest_LXKCTrackCodes> 
</ServiceRequest> 
<ServiceRequest> 
<SRNumber>1</SRNumber> <ServiceRequest_LXKCTrackCodes> <Note>Test2</Note> </ServiceRequest_LXKCTrackCodes> </ServiceRequest> <ServiceRequest> <SRNumber>2</SRNumber> <ServiceRequest_LXKCTrackCodes> <Note>Test3</Note> </ServiceRequest_LXKCTrackCodes> </ServiceRequest>

.... 期望输出：

<ServiceRequest> 
<SRNumber>1</SRNumber> 
<ServiceRequest_LXKCTrackCodes> 
<Note>Test1</Note> 
</ServiceRequest_LXKCTrackCodes> 
<ServiceRequest_LXKCTrackCodes> 
<Note>Test2</Note> 
</ServiceRequest_LXKCTrackCodes> 
<ServiceRequest> 
<SRNumber>2</SRNumber> 
<ServiceRequest_LXKCTrackCodes>
<Note>Test3</Note> 
</ServiceRequest_LXKCTrackCodes> 
</ServiceRequest>

------------------------------------------------------------------------

Answer 1

此转化：

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:key name="kSRByNum" match="ServiceRequest" use="SRNumber"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match=
 "ServiceRequest
    [generate-id()
    =
     generate-id(key('kSRByNum', SRNumber)[1])
    ]
 ">
  <xsl:copy>
   <xsl:apply-templates select="SRNumber"/>
   <xsl:apply-templates select=
    "key('kSRByNum', SRNumber)/ServiceRequest_LXKCTrackCodes"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="ServiceRequest"/>
</xsl:stylesheet>

应用于提供的XML （经过更正以使其格式正确）：

<t>
    <ServiceRequest>
        <SRNumber>1</SRNumber>
        <ServiceRequest_LXKCTrackCodes>
            <Note>Test1</Note>
        </ServiceRequest_LXKCTrackCodes>
    </ServiceRequest>
    <ServiceRequest>
        <SRNumber>1</SRNumber>
        <ServiceRequest_LXKCTrackCodes>
            <Note>Test2</Note>
        </ServiceRequest_LXKCTrackCodes>
    </ServiceRequest>
    <ServiceRequest>
        <SRNumber>2</SRNumber>
        <ServiceRequest_LXKCTrackCodes>
            <Note>Test3</Note>
        </ServiceRequest_LXKCTrackCodes>
    </ServiceRequest>
</t>

生成想要的正确结果：

<t>
   <ServiceRequest>
      <SRNumber>1</SRNumber>
      <ServiceRequest_LXKCTrackCodes>
         <Note>Test1</Note>
      </ServiceRequest_LXKCTrackCodes>
      <ServiceRequest_LXKCTrackCodes>
         <Note>Test2</Note>
      </ServiceRequest_LXKCTrackCodes>
   </ServiceRequest>
   <ServiceRequest>
      <SRNumber>2</SRNumber>
      <ServiceRequest_LXKCTrackCodes>
         <Note>Test3</Note>
      </ServiceRequest_LXKCTrackCodes>
   </ServiceRequest>
</t>

解释：正确使用 Muenchian grouping 和模板匹配。

XSLT的新手，尝试根据元素值消除重复的父级。但是想要合并子级

1 个答案: