如何在循环期间修改foreach()循环中的下一个元素?我认为它与通过引用与变量交谈有关,但我不确定如何。即:
$arr = array( array('color' => 'red', 'type' => 'apple'),
array('color' => 'yellow', 'type' => 'banana'),
array('color' => 'purple', 'type' => 'grape')
);
foreach($arr as $k => $v) {
echo "<br> The ".$v['type'].' fruit is '.$v['color'];
// change the color of the next fruit?
if($v['type'] == 'apple') { $arr[$k+1]['color'] = 'green'; }
}
我想告诉我香蕉是绿色的,但它固执地坚持香蕉是黄色的......
(更新:在我原来的问题中修正了一个愚蠢的逻辑错误。以下标记的答案是正确的。)
答案 0 :(得分:5)
通过获取数组的副本而不是通过引用来循环遍历数组。您需要使用数组值上的&符号&
通过引用遍历数组。
foreach($arr as $k => &$v) {
echo "<br> The ".$v['type'].' fruit is '.$v['color'];
// change the color of the next fruit?
if($v['type'] == 'banana') { $arr[$k+1]['color'] = 'green'; }
}
答案 1 :(得分:0)
$k=array_keys($yourarray);
for($i=0; $i<sizeof ($k); $i++) {
if($yourarray[$k[$i]] == "something") {
$yourarray[$k[$i+1]] = "something else";
}
}
}
抱歉格式化很难得,因为我正在通过电话回复......
答案 2 :(得分:-1)
计数器必须保持不变
$arr = array( array('color' => 'red', 'type' => 'apple'),
array('color' => 'yellow', 'type' => 'banana'),
array('color' => 'purple', 'type' => 'grape')
);
foreach($arr as $k => $v) {
echo "<br> The ".$v['type'].' fruit is '.$v['color'];
// change the color of the next fruit?
if($v['type'] == 'banana') { $arr[$k]['color'] = 'green'; }
// now echo the new color from the original array
echo "<br> The ".$arr[$k]['type'].' fruit is now '.$arr[$k]['color'];
}