在复选框中显示联系人和电话号码

时间:2012-02-24 00:28:43

标签: android listview checkbox contactscontract

我尝试使用此代码在listView中的复选框中显示电话号码:

@Override
protected void onCreate(Bundle savedInstanceState) {
   // TODO Auto-generated method stub
   super.onCreate(savedInstanceState);
   setContentView(R.layout.main1);
   lv = (ListView) findViewById(R.id.contactList);

   Cursor numberCursor = null;
   Cursor peopleCursor = getContentResolver().query(ContactsContract
        .Contacts.CONTENT_URI,null,null
           ,null,null);  

   String [] nb = null ;
   String [] Tname = null;

   if(peopleCursor.getCount()>0)
   {  
       peopleCursor.moveToFirst();

       for(int i=0;i<peopleCursor.getCount();i++)
       {  
           //get number
           numberCursor=getContentResolver().query(ContactsContract
                .CommonDataKinds.Phone.CONTENT_URI, 
                new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER}
                ,ContactsContract.CommonDataKinds.Phone._ID+"="+peopleCursor
                .getString(peopleCursor.getColumnIndex(ContactsContract.Contacts._ID)),  
                null,null);
           numberCursor.moveToFirst(); 

           String number=numberCursor.getString(numberCursor 
                  .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
           nb[i]=number;

           //get name
           String name=peopleCursor.getString(numberCursor
               .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
           Tname[i]=name;

           peopleCursor.moveToNext();                   
       }   

       SimpleCursorAdapter adapter = new SimpleCursorAdapter(this,  
           R.layout.contact_entry, numberCursor,nb, 
           new int[] {R.id.checkBox});

           lv.setAdapter(adapter);

    }

} 

但是我在logcat中遇到了这个错误,我不明白---&gt;

android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0  

1 个答案:

答案 0 :(得分:0)

首先,我认为你应该在使用之前定义nb和Tname的大小:

      String[] Tname  = new String[peopleCursor.getCount()];

      String[] nb = new String[numberCursor.getCount()];

但我认为问题出在您的联系人列表每个人可能有一个或多个电话号码。 因此,peopleCursornumberCursor应该有两个循环。并且您的索引(代码中的i)应仅用于数组Tname